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zvonat [6]
3 years ago
12

Evaluate the quotient of 1.05 x 103 and 1 x 103:

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0
The answer would be Letter C

(1.05 x 10^3)
-----------------
(1 x 10^3)

Divide the 1.05 by 1 and get 1.05
Divide 10^3/10^3 and get 10^(3-3) = 10^0
So: 1.05 x 10^0
Flauer [41]3 years ago
8 0

Answer:

C) 1.05\times 10^0

Step-by-step explanation:

Here, the given expression is,

\frac{1.05\times 10^3}{1\times 10^3}

=\frac{1.05\times 10^3\times 10^{-3}}{1}   (a^m=\frac{1}{a^{-m}})

=1.05\times 10^{3-3}      (a^m.a^n=a^{m+n})

=1.05\times 10^0

Which is the required quotient.

Option 'C' is correct.

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angle AOB = 132 and is also the sum of angles AOD and DOB. Hence 
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angle COD = 141 and is also the sum of angles COB and BOD. Hence 
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Now we add the left sides together and the right sides of equations 1 and 2 together to form a new equation. 

angle AOD + angle DOB + angle COB + angle DOB = 132 + 141       ---> 3 

We should also note that: 
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Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180 and solving for angle DOB:
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15a^3+6a^2b-25ab^2-10b^3
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Answer: 3a

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