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zvonat [6]
3 years ago
12

Evaluate the quotient of 1.05 x 103 and 1 x 103:

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0
The answer would be Letter C

(1.05 x 10^3)
-----------------
(1 x 10^3)

Divide the 1.05 by 1 and get 1.05
Divide 10^3/10^3 and get 10^(3-3) = 10^0
So: 1.05 x 10^0
Flauer [41]3 years ago
8 0

Answer:

C) 1.05\times 10^0

Step-by-step explanation:

Here, the given expression is,

\frac{1.05\times 10^3}{1\times 10^3}

=\frac{1.05\times 10^3\times 10^{-3}}{1}   (a^m=\frac{1}{a^{-m}})

=1.05\times 10^{3-3}      (a^m.a^n=a^{m+n})

=1.05\times 10^0

Which is the required quotient.

Option 'C' is correct.

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Jackson finds a cat stuck in a 20ft tree. Luckily he has a 25foot ladder. If the ladder leans against the tree leaving 6ft of sp
Temka [501]
Hello!

This makes a triangle

The cat is 20 ft high

The triangle is 20 feet high

The is 6 ft between the ladder and the tree

The base is 6 ft long

You use the Pythagorean theorem to solve this

a^{2} + b^{2} =c^{2}

a and b are the base and height

put in the values you know

6^{2} + 20^{2} = c^{2}

square the numbers

36 + 400 = c^{2}

Add

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Take the square root of 436

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Hope this helps!
8 0
3 years ago
If r = 4 and a6 = 192, what is the first term of the sequence?
blagie [28]

Answer:

Answer: Option c. 0.1875 is the first term of the sequence.

Step-by-step explanation:

In this question sixth term of a sequence is given as A(6)= 192

Ratio of terms is given as 4

And we have to calculate the first term of the sequence.

As per formula A(n) = A(1)×r^{n-1}

                         A(6) = A(1)(r)^{6-1}

                          192 = A(1)4^{5}

                           A(1) = \frac{192}{4^{5} }

                                 = 192/1024

                                 =0.1875

So the first term of the sequence will be 0.1875      



5 0
3 years ago
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Answer:

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Step-by-step explanation:

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