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zvonat [6]
3 years ago
12

Evaluate the quotient of 1.05 x 103 and 1 x 103:

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0
The answer would be Letter C

(1.05 x 10^3)
-----------------
(1 x 10^3)

Divide the 1.05 by 1 and get 1.05
Divide 10^3/10^3 and get 10^(3-3) = 10^0
So: 1.05 x 10^0
Flauer [41]3 years ago
8 0

Answer:

C) 1.05\times 10^0

Step-by-step explanation:

Here, the given expression is,

\frac{1.05\times 10^3}{1\times 10^3}

=\frac{1.05\times 10^3\times 10^{-3}}{1}   (a^m=\frac{1}{a^{-m}})

=1.05\times 10^{3-3}      (a^m.a^n=a^{m+n})

=1.05\times 10^0

Which is the required quotient.

Option 'C' is correct.

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Draw 8 lines that are between 1 inch and 3 inches long. Measure each line to the nearest fourth inch, and make a line plot.
IRISSAK [1]

The length of the line is the difference between the endpoints of the line

The length of each line to the nearest fourth inch is 0.25 inch

<h3>How to measure the length of each line</h3>

The length of the horizontal line is given as:

Length = 2 inches

This is calculated as:

Length = 3 inches - 1 inch

Length = 2 inches

8 lines are to be drawn between the 1 inch and 3 inches point.

So, the length (l) of each line is:

l = \frac{2\ inches}{8}

Simplify the fraction

l = \frac{1\ inches}{4}

Divide

l = 0.25\ inch

Hence, the length of each line to the nearest fourth inch is 0.25 inch

Read more about line measurements at:

brainly.com/question/14366932

6 0
1 year ago
Need ASAP
Arlecino [84]

Answer:

1. x = 2

2. x = 21

Step-by-step explanation:

Hope this helps

6 0
2 years ago
Which is a right triangle formed using a diagonal through the interior of the cube? A cube. The top face has points G, B, C, F a
Black_prince [1.1K]

Answer: The correct option is triangle GDC

Step-by-step explanation: Please refer to the picture attached for further details.

The dimensions give for the cube are such that the top surface has vertices GBCF while the bottom surface has vertices HADE.

A right angle can be formed in quite a number of ways since the cube has right angles on all six surfaces. However the question states that the diagonal that forms the right angle runs "through the interior."

Therefore option 1 is not correct since the diagonal formed in triangle BDH passes through two surfaces. Triangle DCB is also formed with its diagonal passing only along one of the surfaces. Triangle GHE is also formed with its diagonal running through one of the surfaces.

However, triangle GDC is formed with its diagonal passing through the interior as shown by the "zigzag" line from point G to point D. And then you have another line running from vertex D to vertex C.

6 0
2 years ago
Read 2 more answers
Show all work and reasoning
Natalija [7]
Split up the interval [2, 5] into n equally spaced subintervals, then consider the value of f(x) at the right endpoint of each subinterval.

The length of the interval is 5-2=3, so the length of each subinterval would be \dfrac3n. This means the first rectangle's height would be taken to be x^2 when x=2+\dfrac3n, so that the height is \left(2+\dfrac3n\right)^2, and its base would have length \dfrac{3k}n. So the area under x^2 over the first subinterval is \left(2+\dfrac3n\right)^2\dfrac3n.

Continuing in this fashion, the area under x^2 over the kth subinterval is approximated by \left(2+\dfrac{3k}n\right)^2\dfrac{3k}n, and so the Riemann approximation to the definite integral is

\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n

and its value is given exactly by taking n\to\infty. So the answer is D (and the value of the integral is exactly 39).
8 0
3 years ago
Please help me ASAP!!!
brilliants [131]

Answer:

The answer is 100% without a doubt A

Step-by-step explanation:

3 0
3 years ago
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