My best choice is A. -76. I might be wrong! Best of luck. :-)
angle AOB = 132 and is also the sum of angles AOD and
DOB. Hence
angle AOD + angle DOB = 132° ---> 1
angle COD = 141 and is also the sum of angles COB and BOD. Hence
angle COB + angle DOB = 141° ---> 2
Now we add the left sides together and the right sides of equations 1 and 2
together to form a new equation.
angle AOD + angle DOB + angle COB + angle DOB = 132 + 141 ---> 3
We should also note that:
angle AOD + angle DOB + angle COB = 180°
Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180
and solving for angle DOB:
180 + angle DOB = 132 + 141
angle DOB = 273 - 180 = 93°
N3Y+7 can have infinate solutions
Answer: 3a
2
(5a+2b)−5b
2
(5a+2b)
2 Factor out the common term 5a+2b5a+2b.
(5a+2b)(3{a}^{2}-5{b}^{2})(5a+2b)(3a
2
−5b
2
)
Step-by-step explanation: