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3 years ago

Find the slope of the line that passses thruogh 1,5 and 10,9

Mathematics

1 answer:

vichka [17]3 years ago

4 0

Answer: The slope is 4/9 or -4/-9.

Step-by-step explanation:

(1,5)

(10,9) Find the difference in the y values and divide it by the difference in the x values.

5-9= -4

1- 10= -9

-4/-9= 4/9

so the slope is 4/9

Using the slope we could also find the y-intercept and write the equation.

5=4/9 (1) + b where b is the y-intercept

5= 4/9 + b

-4/9 -4/9

b= 41/9

Now we will have the equation y= 4/9 + 41/9

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66 tens - 38 tens =<br> Just trying to make sure I’m showing my kids the write way and answer

Leni [432]

Answer:

66 tens - 38 tens= 58 tens

Step-by-step explanation:

You will start off by making the 6 in the ones place a 16 since you can't subtract 6-8 and change the 6 in the tens to a 5 since you borrowed. Hope this helps! :)

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2 years ago

(r-3)(r-1)<br> Help me please!!!

madreJ [45]

Answer:

= r²−4r+3

Step-by-step explanation:

(r - 3) (r - 1)

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2 years ago

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2 years ago

HELP ME OUT HERE! PLS TELL ME HOW U GOT THE ANSWER TOO!

IgorC [24]

Answer: Choice C

$\begin{array}{|c|c|} \cline{1-2}x & y\\\cline{1-2}0 & 1\\\cline{1-2}2 & 2\\\cline{1-2}4 & 3\\\cline{1-2}6 & 4\\\cline{1-2}\end{array}$

=========================================================

Explanation:

There are four marked points on the line.

Each point is of the form (x,y)

The first or left most point is (0,1)
The second point is (2,2)
The third is (4,3)
The fourth is (6,4)

Each of these points is then listed in the table format as shown above.

There are infinitely many other points on the line; however, we only select a few of them to make the table (or else we'd be here all day).

Extra side notes:

The slope of this line is m = 1/2 = 0.5
The y intercept is 1 located at (0,1)
The equation of this line is y = 0.5x+1

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1 year ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago