2. Use the graph of y=-X2 - 2x + 3 to solve

Represent the number 108 in expanded form and exponent

lubasha [3.4K]

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

$\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }$

$\boxed { (a ^ b) ^ c = a ^ { b . c } }$

$\boxed {a ^ b \div a ^ c = a ^ { b - c } }$

$\boxed {\log a + \log b = \log (a \times b) }$

$\boxed {\log a - \log b = \log (a \div b) }$

Let us tackle the problem!

$\texttt{ }$

$108 = 54 \times 2$

$108 = (27 \times 2) \times 2$

$108 = (9 \times 3) \times 2 \times 2$

$108 = (3 \times 3) \times 3 \times 2 \times 2$

$108 = 3^3 \times 2^2$

$\texttt{ }$

<h3>Conclusion:</h3>

The number 108 could be represented in expanded form and exponent as following:

$\boxed{ 108 = 3^3 \times 2^2 }$

$\texttt{ }$

<h3>Learn more</h3>

Coefficient of A Square Root : brainly.com/question/11337634
The Order of Operations : brainly.com/question/10821615
Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

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4 0

3 years ago

Which of the following cannot be used to express the number 8? eight more than zero +8 eight below zero positive eight

MrRa [10]

Eight below zero would express the value -8, negative eight,

but not 8.

7 0

3 years ago

Read 2 more answers

|x^2+x-1|=1 solve for x

Marizza181 [45]

x=−3x=-3

Here the steps

2x+1−1x−1=2xx2−12x+1-1x-1=2xx2-1

x−3(x+1)(x−1)=2x(x+1)(x−1)x-3x+1x-1=2xx+1x-1

(x+1)(x−1)x+1x-1

x−3=2xx-3=2x

x=−3x=-3

So the answer comes out to be x = 3 I hope this was helpful

3 0

4 years ago

Write an equation for the line parallel to the given line that contains C. Help

tangare [24]

There is no photo shown

6 0

3 years ago

What is length of the altitude of the equilateral triangle below?

Lina20 [59]

Answer: OPTION D.

Step-by-step explanation:

Given the equilateral triangle shown in the figure, you need to find the value of the altitude "a".

In order to find the altitude, you can use the following Trigonometric Identity:

$tan\alpha =\frac{opposite}{adjacent}$

In this case you can identify that:

$\alpha=60\°\\\\opposite=a\\\\adjacent=2\sqrt{3}$

Therefore, you can substitute values into $tan\alpha =\frac{opposite}{adjacent}$ :

$tan(60\°)=\frac{a}{2\sqrt{3}}$

Finally, you must solve for the altitude "a". Then, this is:

$(tan(60\°))(2\sqrt{3})=a\\\\a=6$

Notice that this result matches with the value shown in Option D.

3 0

4 years ago