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3 years ago

PLEASE HELP .!!! ILL GIVE BRAINLIEST.. EXRTA POINTS .. DONT SKIP :(( ! ILL GIVE 40 POINTS .

Mathematics

2 answers:

Keith_Richards [23]3 years ago

3 0

Answer:

170

Step-by-step explanation:

Its 170 degrees

Just look at the protractor

vovikov84 [41]3 years ago

3 0

Answer:

it is 170 degree of protactor

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Find the area of the shape below: 9cm 6cm 11cm 15cm

Mandarinka [93]

Answer:

105 cm squared.

Step-by-step explanation:

(9)(6) + (6)(6) + (1/2)(5)(6) = 105.

8 0

2 years ago

How do you to tell the difference between an ellipse, hyperbola, parabola, or circle if all are in standard form?

NeX [460]

Step-by-step explanation:

General form of a conic section is:

Ax² + Bxy + Cy² + Dx + Ey + F = 0

If B = 0:

Parabola: Either x² or y² term, but not both

Circle: x² and y² have the same coefficient

Ellipse: x² and y² have different positive coefficients

Hyperbola: x² and y² have different signs

Otherwise, look at the discriminant.

If B² − 4AC < 0, then the conic is an ellipse.

If B² − 4AC = 0, then the conic is a parabola.

If B² − 4AC > 0, then the conic is a hyperbola.

6 0

3 years ago

Which of the x values are solutions to the inequality 4≥2-4x

skad [1K]

Answer:

x = -1/2

Step-by-step explanation:

Given:

Inequality 4 ≥ 2 - 4x

Find:

Value of x

Computation:

4 ≥ 2 - 4x

4x ≥ -2

x ≥ -1/2

x = -1/2

7 0

3 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

5 0

3 years ago

Evaluate the expression when x=-3.<br> x^2+5x=-4

Neporo4naja [7]

$(-3)^{2} + 5(-3) = - 4\\9 - 15 = - 4\\-6 \neq -4$

This is not possible, as -6 is not equal to -4.

3 0

3 years ago

PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( ! ILL GIVE 40 POINTS .

PLEASE HELP .!!! ILL GIVE BRAINLIEST.. EXRTA POINTS .. DONT SKIP :(( ! ILL GIVE 40 POINTS .