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grandymaker [24]
3 years ago
15

During a circus act, a performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of 7.5 kg a

nd the horizontal component of its velocity is 8.85 m/s when the 73.5-kg performer catches it.
Physics
1 answer:
viva [34]3 years ago
3 0

Answer:

The recoil velocity is 0.819 m/s.

Explanation:

Given that,

Mass of ball m= 7.5 kg

Velocity v= 8.85 m/s

Mass of performer m'= 73.5 kg

Suppose if the performer is on nearly friction less roller skates, we need to calculate his recoil velocity

We need to calculate the recoil velocity

Using law of conservation momentum

mv=(m+m')v'

Where, m = mass of ball

m' = mass of performer

v = velocity of ball

Put the value into the formula

v'=\dfrac{mv}{m+m'}

Put the value into the formula

v'=\dfrac{7.5\times8.85}{7.5+73.5}

v'=0.819\ m/s

Hence, The recoil velocity is 0.819 m/s.

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The temperature inside my refrigerator is about 4 degrees C. If I place a balloon in my fridge that initially has a temperature
maksim [4K]

v

Convert the given temperatures from celsius to kelvin since we are dealing with gas.

To convert to kelvin, add 273.15 to the temperature in celsius.

T1 = 22 + 273.15 = 295.15 k

T2 = 4 + 273.15 = 277.15 k

V1 = 0.5 L

Let's find the final volume (V2).

To solve for V2 apply Charles Law formula below:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

5 0
1 year ago
An object initially at rest experiences an acceleration
lidiya [134]

Answer:

1.4m/s

Explanation:

Average velocity is the total distance covered divided by the total time taken.

 Average velocity  = \frac{total distance }{time }  

 Total time taken  = 5s + 6s  = 11s

The first distance covered  = velocity x time  = 1.4 x 5 = 7m

     second distance covered  = velocity x time  = 1.4 x 6  = 8.4m

So;

  Average velocity  = \frac{7 + 8.4}{11}    = 1.4m/s

5 0
3 years ago
Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid
Serhud [2]

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

8 0
4 years ago
What is the resistance of a 600 W kettle that draws a current of 5.0 A? please answer with steps
lukranit [14]
P=I^2 *R

600 =5.0^2 *R

R=24

Answer: 24 ohms

I hope it’s correcttttttt...

5 1
3 years ago
Determine the kinetic of 600 kg roller coaster car that is moving with the speed of 35.2 m/s.
antiseptic1488 [7]
The answer is 10,560 Joules or 1.1*10^4


Explanation:

Step 1: Calculate
The equation for Kinetic Energy is

Kinetic energy=.5 times Mass times Velocity²
KE=.5*m*v²

so we plug in our numbers
KE=.5*600*35.2²

This works out to be 10,560 Joules or 1.1*10^4
5 0
3 years ago
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