Answer:
Changes in the object's momentum (answer D)
Explanation:
A net force will cause an object to change its velocity, and that will affect the object's momentum, which is defined by the product of the object's mass times its velocity.
So, select the last option (D) in the given list.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The velocity is
in positive x -direction
The speed is ![s = 0.733 \ m/s](https://tex.z-dn.net/?f=s%20%3D%200.733%20%5C%20m%2Fs)
Explanation:
From the question we are told that
The distance from the house to truck is D = 20 m
The distance traveled back to retrieve wind-blown hat is d = 15
The distance from the wind-blown hat position too the truck is k = 20 m
The total time taken is t = 75 s
Generally when calculating the displacement the Justin's backward movement to collect his wind - blown hat is taken as negative
Generally Justin's displacement is mathematically represented as
![L = 20 - 15 + 20](https://tex.z-dn.net/?f=L%20%20%3D%20%2020%20-%2015%20%2B%2020)
=> ![L = 25 \ m](https://tex.z-dn.net/?f=L%20%20%3D%20%2025%20%5C%20m%20)
Generally the average velocity is mathematically represented as
![v = \frac{L}{t}](https://tex.z-dn.net/?f=v%20%20%3D%20%20%5Cfrac%7BL%7D%7Bt%7D)
=> ![v = \frac{25}{75}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B25%7D%7B75%7D)
=>
Generally the distance covered by Justin is mathematically represented as
![R = D+ d + k](https://tex.z-dn.net/?f=R%20%3D%20%20D%2B%20d%20%2B%20k)
=> ![R = 20 + 15 +20](https://tex.z-dn.net/?f=R%20%3D%20%2020%20%2B%2015%20%2B20)
=> ![R = 55 \ m](https://tex.z-dn.net/?f=R%20%3D%20%2055%20%5C%20%20m%20)
Generally Justin's average speed over a 75 s period is mathematically represented as
![s = \frac{R}{ t}](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7BR%7D%7B%20t%7D)
=> ![s = \frac{55}{ 75}](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B55%7D%7B%2075%7D)
=> ![s = 0.733 \ m/s](https://tex.z-dn.net/?f=s%20%3D%200.733%20%5C%20m%2Fs)
Explanation:
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D. all of the above
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The two wires carry current in opposite directions: this means that if we see them from above, the magnetic field generated by one wire is clock-wise, while the magnetic field generated by the other wire is anti-clockwise. Therefore, if we take a point midway between the two wires, the resultant magnetic field at this point is just the sum of the two magnetic fields, since they act in the same direction.
Therefore, we should calculate the magnetic field generated by each wire and then calculate their sum. We are located at a distance r=0.10 m from each wire.
The magnetic field generated by wire 1 is:
![B_1= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} NA^{-2} )(20 A)}{2 \pi (0.10 m)}= 4 \cdot 10^{-5}T](https://tex.z-dn.net/?f=B_1%3D%20%5Cfrac%7B%5Cmu_0%20I%7D%7B2%20%5Cpi%20r%7D%3D%20%5Cfrac%7B%284%20%5Cpi%20%5Ccdot%2010%5E%7B-7%7D%20NA%5E%7B-2%7D%20%29%2820%20A%29%7D%7B2%20%5Cpi%20%280.10%20m%29%7D%3D%20%204%20%5Ccdot%2010%5E%7B-5%7DT)
The magnetic field generated by wire 2 is:
![B_2= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} NA^{-2} )(5.0 A)}{2 \pi (0.10 m)}= 1 \cdot 10^{-5}T](https://tex.z-dn.net/?f=B_2%3D%20%5Cfrac%7B%5Cmu_0%20I%7D%7B2%20%5Cpi%20r%7D%3D%20%5Cfrac%7B%284%20%5Cpi%20%5Ccdot%2010%5E%7B-7%7D%20NA%5E%7B-2%7D%20%29%285.0%20A%29%7D%7B2%20%5Cpi%20%280.10%20m%29%7D%3D%201%20%5Ccdot%2010%5E%7B-5%7DT)
And so, the resultant magnetic field at the point midway between the two wires is