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Wewaii [24]
3 years ago
5

Carla is babysitting her 2-year-old nephew for the first time. While her back is turned just for a moment, he touches the pan sh

e just took out of the oven. He pulls his finger away quickly, and a few moments later begins to scream. Why is his screaming delayed (in comparison to his response of pulling away his finger)?
Physics
1 answer:
defon3 years ago
4 0

Answer:

Screaming is an emotional response triggered by the brain which receives information about the pain later as compared to pulling away of finger which is a reflex action facilitated by the spinal cord that has a quicker-time to response.

Explanation:

Reflex action happens when part of our body comes to contact with an object which can cause harm and you tend to quickly withdraw that part of the body.Reflex action happens quicker before the brain gets the time to process information about the harm.

When the baby touched the hot pan, at point of contact, skin receptors send nerve impulses to the spinal cord. Interneurons in the spinal cord relay a response to motor neurons to stimulate muscle contraction making the baby to pull his finger away.This happens so fast before the brain receives the message later to trigger emotional response(screaming).

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Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?
MrMuchimi
 T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r 

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance. 
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect, 

Point 1: 
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r

Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m 
The distance between the two points then is equal to 7.07 m.


</span>
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2 years ago
Two long, parallel wires separated by 2.00 cm carry currents in opposite directions. The current in one wire is 1.75 A, and the
Natasha_Volkova [10]

The force per unit length between the two wires is 6.0\cdot 10^{-5} N/m

Explanation:

The magnitude of the force per unit length exerted between two current-carrying wires is given by

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where

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I_1, I_2 are the currents in the two wires

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For the wires in this problem, we have

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Substituting into the equation, we find

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3 years ago
A diffraction pattern forms when light passes through a single slit. The wavelength of the light is 691 nm. Determine the angle
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Explanation:

Given that,

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(a) Slit width, a=3.8\times 10^{-4}\ m

The angle that locates the first dark fringe is given by :

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sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-4}}

\theta=0.104^{\circ}

(b) Slit width, a=3.8\times 10^{-6}\ m

The angle that locates the first dark fringe is given by :

sin\theta=\dfrac{\lambda}{a}

sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-6}}

\theta=10.47^{\circ}

Hence, this is the required solution.

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