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Wewaii [24]
4 years ago
5

Carla is babysitting her 2-year-old nephew for the first time. While her back is turned just for a moment, he touches the pan sh

e just took out of the oven. He pulls his finger away quickly, and a few moments later begins to scream. Why is his screaming delayed (in comparison to his response of pulling away his finger)?
Physics
1 answer:
defon4 years ago
4 0

Answer:

Screaming is an emotional response triggered by the brain which receives information about the pain later as compared to pulling away of finger which is a reflex action facilitated by the spinal cord that has a quicker-time to response.

Explanation:

Reflex action happens when part of our body comes to contact with an object which can cause harm and you tend to quickly withdraw that part of the body.Reflex action happens quicker before the brain gets the time to process information about the harm.

When the baby touched the hot pan, at point of contact, skin receptors send nerve impulses to the spinal cord. Interneurons in the spinal cord relay a response to motor neurons to stimulate muscle contraction making the baby to pull his finger away.This happens so fast before the brain receives the message later to trigger emotional response(screaming).

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Differences between fundamental and derived quantities​
monitta

Answer:

Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.

6 0
2 years ago
Could you please help me on number four
sleet_krkn [62]
What is it asking? It is sort of blurry
3 0
3 years ago
An object with a mass of 1 kg is attached to one end of a cord 10 m long. The cord will break if its tension exceeds 10 N. The o
faust18 [17]

Answer:

10 m/s

Explanation:

∑F = ma

T = m v² / r

10 N = (1 kg) v² / (10 m)

v = 10 m/s

3 0
3 years ago
A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q separated by a distance s.
marishachu [46]

Answer:

a) the magnitude of the force is

F= Q(\frac{kqs}{r^3}) and where k = 1/4πε₀

F = Qqs/4πε₀r³

b)  the magnitude of the torque on the dipole

τ = Qqs/4πε₀r²

Explanation:

from coulomb's law

E = \frac{kq}{r^{2} }

where k = 1/4πε₀

the expression of the electric field due to dipole at a distance r is

E(r) = \frac{kp}{r^{3} } , where p = q × s

E(r) = \frac{kqs}{r^{3} } where r>>s

a) find the magnitude of force due to the dipole

F=QE

F= Q(\frac{kqs}{r^3})

where k = 1/4πε₀

F = Qqs/4πε₀r³

b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces

τ = F sinθ × s

θ = 90°

note: sin90° = 1

τ = F × r

recall  F = Qqs/4πε₀r³

∴ τ = (Qqs/4πε₀r³) × r

τ = Qqs/4πε₀r²

8 0
3 years ago
A corvette starts from rest and travels 69.0 meters in 50 s. What is its acceleration?
devlian [24]

Answer:

0.0552 m/s²

Explanation:

Given:

Δx = 69.0 m

v₀ = 0 m/s

t = 50 s

Find: a

Δx = v₀ t + ½ at²

69.0 m = (0 m/s) (50 s) + ½ a (50 s)²

a = 0.0552 m/s²

4 0
3 years ago
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