Block 1, of mass m₁ = 1.30 kg , moves along a frictionless air track with speed v₁ = 29.0 m/s. It collides with block 2, of mass
m₂ = 39.0 kg, which was initially at rest. The blocks stick together after the collision.
A: Find the magnitude π of the total initial momentum of the two-block system. Express your answer numerically.
B: Find
, the magnitude of the final velocity of the two-block system. Express your answer numerically.
C: what is the change
initial in the two block systems kinetic energy due to the collision ? Express your answer numerically in joules.
A: Find the magnitude π of the total initial momentum of the two-block system. Express your answer numerically.
B: Find
C: what is the change
1 answer:
You might be interested in
Answer:
-22,150 N
Explanation:
When the youngster jumps off the platform, during the fall her initial potential energy is converted into kinetic energy, according to the law of conservation of energy. Therefore, we can write:
where the term on the left is the potential energy while the term on the right is the kinetic energy, and where
m = 50.0 kg is the mass of the youngster
is the acceleration due to gravity
h = 1.00 m is the heigth of the platform
u is the speed of the youngster as she reaches the floor
Solving for u,
Then, when the youngster hits the floor, the force exerted on her during the deceleration is given by:
where is her change in momentum, and where
m is the mass
v = 0 is the final velocity (she comes to a stop)
u = 4.43 m/s is the initial velocity
is the duration of the collision
Substituting,
And the negative sign means the direction of the force is opposite to the motion (so, upward).