Answer: 322
Step-by-step explanation:
23 students × 14 homework
=322 problems
The teacher will have to grade 322 problems
Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Answer:
Slope <em>m</em> (Gradient) = 3
y-intercept: (0, -5)
General Formulas and Concepts:
<u>Algebra I</u>
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
y = 3x - 5
<u>Step 2: Break function</u>
Slope <em>m</em> = 3
y-intercept <em>b</em> = -5
Volume of cylinder = πr²h = π x 4² x 6 = 96π
volume of cone = 1/3πR²H = 1/3π x 8² x 12 = 256π
You can see that volume of cone is more than twice of volume of cylinder. So she is not correct