How do we find the surface area of this prism? ( Cube )

Mathematics

1 answer:

kenny6666 [7]4 years ago

4 0

You would find the area of the squares you drew in the net and then add them so 9•9•6

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The density of silver (Ag) is 10.5 g/cm3. Find the mass of Ag that occupies 965 cm3 of space.

Luda [366]

Answer:

<h3>The answer is 10132.5 g</h3>

Step-by-step explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of silver = 965 cm³

density = 10.5 g/cm³

The mass of silver is

mass = 965 × 10.5

We have the final answer as

Hope this helps you

5 0

4 years ago

Given the graph of y=f(x), shown as a green curve, drag the green movable points to draw the graph of y=−f(x). When the green li

Sunny_sXe [5.5K]

The <em>resulting</em> function is presented in the image attached below.

In this question we know the graphic of a function and we must draw a <em>new</em> function which is the reflection of the <em>original</em> one around the x-axis. Mathematically speaking, a reflection a around the x-axis is defined by the following operation:

$f'(x) = f(x) - 2\cdot [f(x) - 0]$

$f'(x) = - f(x)$ (1)

Which means that the <em>reflected</em> function is equal to the <em>original</em> function multiplied by -1.

Now, we proceed to represent the <em>reflected</em> function graphically.

We kindly invite to check this question on reflections: brainly.com/question/15487308

8 0

3 years ago

What is the simplified form of the following expression? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 2

finlep [7]

To solve such questions we need to know more about expression.

<h2 /><h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.

<h2 /><h2 /><h2>Given to us,</h2>

$2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-16\sqrt[4]{2y}+13\sqrt[4]{4}-10\sqrt[4]{2y}+35\sqrt[4]{x}-18\sqrt[4]{2y}$

rearranging we get,

$=2\sqrt[4]{16x}+3\sqrt[4]{81x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{4}+35\sqrt[4]{x}-2\sqrt[4]{2y}-4\sqrt[4]{32y}-4\sqrt[4]{32y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$

we know that,

$\sqrt[4]{81}=3\\\sqrt[4]{16}=2\\\sqrt[4]{32}=2\sqrt[4]{2}\\$

therefore,

$=4\sqrt[4]{x}+9\sqrt[4]{x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{x}+35\sqrt[4]{x}-2\sqrt[4]{2y}-8\sqrt[4]{2y}-8\sqrt[4]{2y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$