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Gala2k [10]
3 years ago
13

How do we find the surface area of this prism? ( Cube )

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0
You would find the area of the squares you drew in the net and then add them so 9•9•6
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THere are 60 dogs in the park. 20% of them are golden retrievers. How many golden retrievers are there in the park? Use a propor
Mrac [35]

Answer:

There are 12 golden retrievers in the park

Step-by-step explanation:

100% is 60 dogs so if 100% is equal to 60 then 20% should be the answer.

100 ÷ 5= 20

60 ÷ 5= 12

amount of dogs in the park : golden retrievers

60 : 12

3 0
2 years ago
Can someone tell me what the answer for <br> 2 kos60° + tan 45 ° ​
enot [183]

Answer:

{ \tt{2 \cos60 \degree +  \tan(45 \degree) }} \\  \\  = 2(0.5) + 1 \\  = 1 + 1 \\  = 2

8 0
3 years ago
I FREAKING NEED HELPPP!!!
Ratling [72]

Answer:

\boxed{\begin{bmatrix}  3 &  - 1 \\  - 3 & 4\end{bmatrix}  = 12 - 3 =  \boxed{9} }\\ \\  \boxed{\begin{bmatrix}   -12 &  - 1 \\  12 &  5\end{bmatrix}  =  - 60-  ( - 12) =  \boxed{ - 48}} \\  \\ \boxed{\begin{bmatrix}  0&  - 1 \\  17 & 4\end{bmatrix}  = 0 -( - 17 )=  \boxed{17}} \\  \\\boxed{ \begin{bmatrix}  8&  - 1 \\  -  4 &  - 1\end{bmatrix}  =  - 8 - 4 =  \boxed{ - 12} }\\  \\ \boxed{\begin{bmatrix}  2 &  - 1 \\  2 &  - 1\end{bmatrix}  =  - 2 - ( - 2) =  \boxed{0}} \\  \\ \boxed{ \begin{bmatrix}  1 &  0\\  0 &1\end{bmatrix}  = 1 - 0 =  \boxed{1}}

Step-by-step explanation:

the \: determinant \: of  \: a \: matrix : A  \to\\If  \: A  =\begin{bmatrix}  x & y \\ a & b \end{bmatrix} \: then : \\  its \: determinant \: is \: givn \: by \to \\  |A|  =  (b \times x) - (a \times y) \\  \boxed{|A|  = bx - ax}

♨Rage♨

5 0
2 years ago
Photo attached please hel p
dlinn [17]

Answer:

d

Step-by-step explanation:

3 0
3 years ago
A circular plate has circumference 32 inches. What is the area of this​ plate? Use 3.14 for pi. The area of this plate is about
Novosadov [1.4K]

Answer:

A = 82.53 in²

Step-by-step explanation:

We use the circumference equation C = 2πr and the area equation A = πr².

Using the first equation and the given circumference (32 in), we find the radius of the circle, and then use this result to find the area of the circle.

         

                                         C                            32 in

C = 2πr becomes r = ----------- and here r = ---------- = 5.10 in

                                        2π                            6.28

Then the area of the circle is A = πr², which here is A = 3.14(5.10 in)², which, when rounded off to two decimal places, is A = 82.53 in²

6 0
3 years ago
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