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Gala2k [10]
4 years ago
13

How do we find the surface area of this prism? ( Cube )

Mathematics
1 answer:
kenny6666 [7]4 years ago
4 0
You would find the area of the squares you drew in the net and then add them so 9•9•6
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If m∠W = 105° and m∠Y = 75°, then m∠X = <br><br> Please show your work, so I know the process.
Paha777 [63]

Answer:

30°

Step-by-step explanation:

First we must know that the sum of the interior angles of a triangle sum up to 180°.  Furthermore, a straight line is also 180°.  By using these what we know we can determine what the value of m∠X is.

First we know that m∠W and m∠Z make up a straight line, since m∠W is 105° it follows that:

180° = m∠W + m∠Z

And so:

m∠Z = 180° - m∠W = 180°-105° = 75°

m∠Z = 75°

Now, we also know that the sum of m∠X + m∠Y + m∠Z = 180° and so:

m∠X = 180° - m∠Y - m∠Z

m∠X = 180° - 75° - 75° = 30°

Therefore, m∠X = 30°


7 0
4 years ago
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What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%2B3%7D%7B8%7D" id="TexFormula1" title="\frac{a+3}{8}" alt="\frac{a+3}{8}"
KonstantinChe [14]

Answer: \frac{2a+6}{8a}

Step-by-step explanation:

\frac{2(a+3)}{8a}=\frac{2a+6}{8a}

4 0
2 years ago
Solve the inequality for y.<br> y-5&lt;-14
dedylja [7]
The answer is y=-9
negative 9 remember that

Move the constant to the right-hand side and change its sign and calculate
5 0
3 years ago
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Need help Identify three solutions of the graph shown
tester [92]
The solutions are basically the points on the graph that the line passes through. The best way to pick them is to use the whole numbers that are on the corners of the little boxes instead of the middle.

(4, -5)
(3, -3)
(1, 1)
(0, 3)
(-1, 5)
and so on.
6 0
4 years ago
If a leg of a 45-45-90 triangle is 11 then the hypotenuse is...
iragen [17]

Answer:

c)11√2

Step-by-step explanation:

Given that two of the angles are equal ,each measuring 45 degrees then two legs will be equal as well each measuring 11 units. We have a right angled triangle with two sides given and we are required to determine the hypotenuse. We use Pythagoras theorem;

hypotenuse^2 = 11^2 + 11^2

hypotenuse ^2 = 242

hypotenuse = \sqrt{242}

hypotenuse = 11\sqrt{2}

3 0
4 years ago
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