The equation which models the distance (d) of the weight from its equilibrium after time (t) is equal to d = -9cos(2π/3)t.
<h3>What is the period of a cosine function?</h3>
The period of a cosine function simply means the total length (distance) of the interval of values on the x-axis over which a graph lies and it's repeated.
Since the weight attached is at its lowest point at time (t = 0), therefore, the amplitude of equation will be negative nine (-9)
For the angular velocity at time period (t = 3s), we have:
ω = 2π/T
ω = 2π/3
Mathematically, the standard equation of a cosine function is given by:
y = Acos(ω)t
Substituting the given parameters into the formula, we have;
d = -9cos(2π/3)t.
Read more on cosine function here: brainly.com/question/4599903
Answer:
87
Step-by-step explanation:
all the angles of a triangle out of 180 so subtract the two numbers you have from 180
Answer:
Step-by-step explanation:
Let's solve the second equation for a to later on replace it in the first equation.
Now plug this into the first equation.
Distribute the 9
Break down the fraction.
Simplify.
Subtract 
Combine like terms.
Muliply by the reciprocal or inverted fraction next to b.
Now plug this value into any of the equations to find the value of a.
If T is the midpoint of SU, then ST ≅ TU.
Therefore we have the equation:
6x = 2x + 32 <em>subtract 2x from both sides</em>
4x = 32 <em>divide both sides by 4</em>
x = 8
ST = 6x → ST = 6(8) = 48
TU = ST, therefore ST = 48
SU = ST + TU = 2ST, therefore SU = 2(48) = 96
<h3>Answer: ST = 48, TU = 48, SU = 96</h3>
