Answer:
allopolyploidy
Explanation:
Polyploidy is the condition by which a cell might have more than two chromosome sets that form homologous pairs. It might occur due to a failure or abnormality in cell division.
Autopolyploidy
Refer to a type of polyploidy in which an organism has more than two copies of homologous chromosomes. It results from the duplication of a group of chromosomes of the same species. Autopolyploid individuals have <u>at least three groups of homologous chromosomes</u>. Autopolyploidy is produced by the<u> gamete fusion of the same progenitor - same species</u>-, duplicating the number of chromosomes of diploid species. The autopolyploid cell has groups of homologous chromosomes. Autopolyploidy is produced mainly due to non-disjunction during meiosis.
Allopolyploidy
Refer to another type of polyploidy in which species have more than three sets of chromosomes in their cells. Allopolyploidy <u>occurs when two different species mate</u>, leading to the fusion of gametes that belong to different species and produce a new hybrid. The chromosomic complement has more than two copies of chromosomes. The hybrid is infertile with the parental species. The allopolyploid cells have chromosome groups that are not homologous.
In the exposed example two different species mate and produce a hybrid species.
Answer:
the environment and parasites
Answer:
a. Bands at 1kb, 6kb and 8kb
Explanation:
The EcoRI and BamHI are the restriction enzymes which cut the DNA sequence especially a plasmid at specific sites called the restriction sites.
The restriction enzymes produces bands of specific length therefore these restriction enzymes are used to estimate the approximate length of the DNA.
In the given question, the
1. EcoRI- produces two strands of 7 kb and 8 kb
2. BamHI- produces two strands of 1kb and 14kb
This shows that the length of DNA sequence is 15kb
But when the DNA strand are digested with both the enzymes simultaneously then it will produce three bands as:
i) 14 kb can be broken down in 2 bands of 6 kb and 8 kb
ii) 1 kb band is already produced by the Bam HI.
This shows that 1+6+8= 15 kb
Thus, Option-A is correct.
Answer:
Yes
Explanation:
Range rule of thumb predicts the Range to be a multiple of 4 of the standard deviation or to be four times the standard deviation. Making the usual values equal to 2 standard deviations distanct of the mean of the data distribution.
In a given distribution with mean and standard deviation that is obtained, the usual values in mean (as seen in the attached image).
2*standard deviation and mean + 2*standard deviation.
If the data point is not up to the mean
- 2* standard deviation is taken to be significantly low.
If the data point is more than the mean
+ 2*standard deviation is taken to be significantly high.
Let's take the xbar to be the mean and s as standard deviaiton
Given,
mean, xbar = 1116.2
standard deviation, s =127.7
The range rule of thumb shows that the usual values are within 2 standard deviations from the mean
Lower boundary
= xbar - 2s
= 1116.2 - 2(127.7)
= 860.8
Upper boundary
= xbar + 2s
= 1116.2 + 2(127.7)
= 1371.6
We should note that 1411.6 is not between 860.8 and 1371.6, which connotes that 1411.6cm^3 is unusually high.
