Answer:
90%
Explanation:
Data obtained from the question include:
Actual yield = 585g
Theoretical yield = 650g
%yield =?
%yield = Actual yield /Theoretical yield x100
% yield = 585/650 x 100
% yield = 90%
The volume of ammonia gas is 4096 mL.
Explanation:
As per the kinetic theory of gases, the volume occupied by gas molecules will be directly proportional to the temperature and number of moles of the gas molecules. Similarly, the volume occupied by gas molecules will be inversely proportional to pressure.
PV = nRT
So, V = nRT/P
As R = 0.082 L atm mol⁻¹ K⁻¹ , T = 273 K and P = 1 atm with n = 0.183 mol
Then,
V=(0.183*0.082*273)/1
V = 4.096 L = 4096 mL.
Thus, the volume of ammonia gas is 4096 mL.
Answer: 63.88 atm
Explanation:
To answer this, we use the formula PV = nRT since the asumption is that the gas has an ideal behavior
where number of mole = 2.60 mol, R(gas constant) = 0.08205746 L atm/K mol,
T = 251 ∘C = (251 + 273) K = 524 K, Volume = 1.75 L
Making Pressure the subject of the formula, we have
P = nRT/V = 2.6 * 0.08205746 * 524/2.75 = 63.88 atm
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It is the 4th one that is correct and balanced
