Answer:
a. Vₐ = 111.5282 + 1.29396m
b. For m = 0.100m; Vₐ = 111.6576
Explanation:
The partial molar volume of compound A in a mixture of A and B is defined as
:
Where V is volume and n are moles of a.
a. As molality is proportional to moles of substance, partial molar volume of glucose can be defined as:
Vₐ = dV / dm = d(1001.93 + 111.5282m + 0.64698m²) / dm
<em>Vₐ = 111.5282 + 1.29396m</em>
b. Replacing for m = 0.100m:
Vₐ = 111.5282 + 1.29396×0.100
<em>Vₐ = 111.6576</em>
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I hope it helps!
Answer:
=933.3 grams
Explanation:
Magnesium reacts with oxygen producing magnesium oxide according to the following equation.
2Mg₍s₎ + O₂₍g₎→ 2MgO₍s₎
From the above equation, 2 moles of Magnesium produces 2 moles of magnesium oxide. Therefore the ratio of magnesium to magnesium oxide produced is 1:1
1 mole of magnesium oxide has a mass of: 24+16 =40 grams
560 grams of magnesium=560/24 moles
=70/3 moles.
Since the ratio is 1:1 the reaction produces 70/3 moles of magnesium oxide.
70/3 moles of MgO= 70/3 moles× 40 grams
=933.3 grams
POH = 14 - pH
pOH = -log [OH-]
Okay so, the molar mass (Mr) of O2 is 32g
moles = mass/Mr
moleS= 32.4/32= 1.0125mol
the Mr of KCl is 39.1+35.5= 74.6g
the ratio of moles of KCl to O2 is 2 : 3
therefore moles of KCl is (1.0125/3)×2= 0.675mols
mass =moles×Mr=0.675×74.6= 50.355g
rounds up to 50.3g therefore last answer is correct
<u>Answer:</u> The mass of the nitrous oxide gas produced is 0.011 kg.
<u>Explanation:</u>
To calculate the mass of the gas, we use the formula:
We are given:
Specific density of the gas =
Mass of the gas = ? kg
Volume of the gas = (Conversion Factor: )
Putting values in above equation, we get:
Hence, the mass of the nitrous oxide gas produced is 0.011 kg.