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Georgia [21]
3 years ago
6

To prevent tank rupture during deep-space travel, an engineering team is studying the effect of temperature on gases confined to

small volumes. What is the pressure of 2.60 mol of gas D measured at 251 ∘C in a 1.75-L container assuming ideal behavior? Express your answer with the appropriate units.
Chemistry
1 answer:
uranmaximum [27]3 years ago
6 0

Answer: 63.88 atm

Explanation:

To answer this, we use the formula PV = nRT since the asumption is that the gas has an ideal behavior

where number of mole = 2.60 mol, R(gas constant) = 0.08205746 L atm/K mol,

T = 251 ∘C = (251 + 273) K = 524 K, Volume = 1.75 L

Making Pressure the subject of the formula, we have

P = nRT/V = 2.6 * 0.08205746 * 524/2.75 = 63.88 atm

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Which element among these has the most negative electron affinity (i.e., has most exothermic electron affinity). A. H B. Li C. C
OleMash [197]

Answer:

D. F

Explanation:

Electron affinity is defined as the change in energy (in kJ/mole) of a neutral atom (in the gaseous phase) when an electron is added to the atom to form a negative ion. In other words, the neutral atom's likelihood of gaining an electron.

The electron affinity values of the following elements is given;

Electron Affinity of Hydrogen is 72.8 kJ/mol.

Electron Affinity of Lithium is 59.6 kJ/mol

electron affinity of carbon is 153.9 kJ mol‑1

Electron Affinity of Fluorine is 328 kJ/mol

The electron affinity of neon is 0 kJ mol‑1.

When nonmetals gain electrons, the energy change is usually negative because they give off energy to form an anion (exothermic process); thus, the electron affinity will be negative.

Nonmetals have a higher electron affinity than metals, meaning they are more likely to gain electrons than atoms with a lower electron affinity.

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7 0
4 years ago
Write the word and balanced chemical equations for the reaction between:
lesantik [10]

Answer:

Potassium hydroxide + Hydrochloric acid → Potassium chloride + Water.

7 0
3 years ago
Read 2 more answers
I'm kinda stumped here :/
maria [59]

Answer:

To prepare 20,0 mL of the liquid mixture you should mix 15,3 mL of CHCl₃ with 4,7 mL of CHBr₃

Explanation:

Here you have two variables: The volume of both CHCl₃ (X) and CHBr₃ (Y). To find these two variables you must have, at least, two equations.

You know total volume is 20,0 mL. Thus:

X + Y = 20,0 mL (1)

The other equation  is:

\frac{X}{20,0mL\\} × 1,492 g/mL + \frac{Y}{20,0 mL} × 2,890 g/mL = 1,82 g/mL (2)

If you replace (1) in (2):

\frac{X}{20,0mL\\} × 1,492 g/mL + \frac{20,0 mL - X}{20,0 mL} × 2,890 g/mL = 1,82 g/mL

Solving:

X = 15,3 mL

Thus, using (1):

20,0 mL - 15,3 mL = Y = 4,7 mL

Thus, to prepare 20,0 mL of the liquid mixture you must mix 15,3 mL of CHCl₃ with 4,7 mL of CHBr₃.

I hope it helps!

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