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Nataliya [291]
4 years ago
7

The copper and aluminum electrodes are connected in a battery.

Chemistry
1 answer:
Dmitry [639]4 years ago
5 0

a. Which is the anode?

Al is more reactive than the Cu, because the reduction potential of Al is -1.676 V, so would turn to ions easily hence it would give electrons and form a cation and so it will be the anode.

 

b. Which is oxidized?

Copper is the cathode, because of its reduction potential +0.34 V, which has a higher affinity for electrons and so it will be the oxidizing agent which means the Al is oxidized.  

c. What will the battery voltage be?

The voltage of the battery we can be calculated by using the reduction potentials of both elements:

E°battery = E°cathode - E°anode = E°Cu - E°Al = 0.34 - (-1.676) = 2.016 V

The cell have a spontaneous reaction because the voltage has a positive sign.

d. Write a balanced net ionic equation for the reaction that takes place.  

Al + 3 Cu⁺ ----> Al³⁺ + 3 Cu  

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Which compounds are bases in aqueous solution according to brønsted–lowry theory?.
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Ammonia compounds are bases in aqueous solution according to brønsted–lowry theory.

<h3>What are bases?</h3>

A base is a substance that can neutralize the acid by reacting with hydrogen ions.

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3 0
2 years ago
PLEASE HELP!!!!!!!
dsp73

Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles

\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles

The balanced chemical equation is:

2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu  

According to stoichiometry :

3 moles of CuCl_2 require = 2 moles of Al

Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

As 3 moles of CuCl_2 give = 2 moles of AlCl_3

Thus 0.33 moles of CuCl_2 give =\frac{2}{3}\times 0.33=0.22moles  of AlCl_3

Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

5 0
3 years ago
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