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3 years ago

The copper and aluminum electrodes are connected in a battery.

Chemistry

1 answer:

Dmitry [639]3 years ago

5 0

a. Which is the anode?

Al is more reactive than the Cu, because the reduction potential of Al is -1.676 V, so would turn to ions easily hence it would give electrons and form a cation and so it will be the anode.

b. Which is oxidized?

Copper is the cathode, because of its reduction potential +0.34 V, which has a higher affinity for electrons and so it will be the oxidizing agent which means the Al is oxidized.

c. What will the battery voltage be?

The voltage of the battery we can be calculated by using the reduction potentials of both elements:

E°battery = E°cathode - E°anode = E°Cu - E°Al = 0.34 - (-1.676) = 2.016 V

The cell have a spontaneous reaction because the voltage has a positive sign.

d. Write a balanced net ionic equation for the reaction that takes place.

Al + 3 Cu⁺ ----> Al³⁺ + 3 Cu

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3 years ago

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3 years ago

Read 2 more answers

Please help!! i need the answer ASAP!

nirvana33 [79]

Answer:

23.34 %.

Explanation:

The percentage of water must be calculated as a mass percent.

We need to find the mass of water, and the total mass in one mole of the compound. For that we need to use the atomic masses of each element and take in consideration the number of atoms of each element in the formula unit.

Atomic masses of the elements:

Cd: 112.411 g/mol, N: 14.0067 g/mol, O: 15.999 g/mol, and H: 1.008 g/mol.

Mass of the formula unit:

Cd(NO₃)₂•4H₂O

mass of the formula unit = (At. mass of Cd) + 2(At. mass of N) + 10(At. mass of O) + 8(At. mass of H) = (112.411 g/mol) + 2(14.0067 g/mol) + 10(15.999 g/mol) + 8(1.008 g/mol) = 308.5 g/mol.

Mass of water in the formula unit:

mass of water = (4 × 2 × 1.008 g/mol) + (4 × 15.999 g/mol) = 72.0 g/mol.

So, the percent of water in the compound = [mass of water / mass of the formula unit] × 100 = [(72.0 g/mol)/(308.5 g/mol)] × 100 = 23.34 %

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3 years ago