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emmasim [6.3K]
3 years ago
12

Which substances pass through a leaf's stomata?

Chemistry
2 answers:
Vilka [71]3 years ago
7 0
Carbon dioxide pass through a leaf stomata.
Orlov [11]3 years ago
6 0

Oxygen can pass through the leafs stomata

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What is the minimum pressure in kPa that must be applied at 25 °C to obtain pure water by reverse osmosis from water that is 0.1
Yuri [45]

Answer:

The minimum pressure should be 901.79 kPa

Explanation:

<u>Step 1: </u>Data given

Temperature = 25°C

Molarity of sodium chloride = 0.163 M

Molarity of magnesium sulfate = 0.019 M

<u>Step 2:</u> Calculate osmotic pressure

The formula for the osmotic pressure =

Π=MRT.

⇒ with M = the total molarity of all of the particles in the solution.

 ⇒ R = gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 25 °C = 298 K

NaCl→ Na+ + Cl-

MgSO4 → Mg^2+ + SO4^2-

M = 2(0.163) + 2(0.019 M)

M = 0.364 M

Π = (0.364 M)(0.08206 atm-L/mol-K)(25 + 273 K)

Π = 8.90 atm

(8.90 atm)(101.325 kPa/atm) = 901.79 kPa

The minimum pressure should be 901.79 kPa

6 0
3 years ago
An 8.0 L sample of neon gas at 300. K exerts a pressure of 900. kPa. If the gas is compressed to 2.0 L and the temperature is ra
svetoff [14.1K]

Answer:

7200 kPa

Explanation:

Applying,

PV/T = P'V'/T'................ Equation 1

Where P = Initial pressure of neon gas, V = Initial volume of neon gas, T = Initial temperature of neon gas, P' = Final pressure of neon gas, V' = Final volume of neon gas, T' = Final Temperature of neon gas

Make P' the subject of the equation

P' = PVT'/V'T.............. Equation 2

Given: P = 900 kPa, V = 8.0 L, T = 300 K, V' = 2.0 L, T' = 600 K

Substitute these values into equation 2

P' = (900×8×600)/(2×300)

P' = 7200 kPa

6 0
3 years ago
Which set of properties distinguishes potential energy from kinetic energy?
fenix001 [56]
Kinetic energy is energy possessed by a body by virtue of its movement.

Potential energy is the energy possessed by a body by virtue of its position or state.


3 0
3 years ago
A student burned 0.250 g of magnesium metal in an open crucible.Oxygen from the air combined with the metal forming magnesium ox
Varvara68 [4.7K]

Answer:

0.171 grams of oxygen combined with the metal.

Explanation:

2Mg+O_2\rightarrow 2MgO

Mass of magnesium oxide produced = 0.421 g

Mass of magnesium metal used = 0.250 g

Suppose reaction completely converts the magnesium into magnesium oxide.

Mass of oxygen combined with magnesium = m

0.421 g = 0.250 g + m

m =  0.421 g - 0.250 g = 0.171 g

0.171 grams of oxygen combined with the metal.

5 0
3 years ago
What is the gravitational force between you and Earth?<br><br>A. Weight<br>B. Force​
damaskus [11]

Answer:

force

Explanation:

mark brainliest?

8 0
3 years ago
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