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olga_2 [115]
3 years ago
5

15 points! I will give Brainliest and heart! Answer ASAP but with DETAIL, I need step - by - step, clear words, correct grammar.

A pair of equations is shown below: y = 3x − 5 y = 6x − 8 Part A: Explain how you will solve the pair of equations by substitution or elimination. Show all the steps and write the solution. (5 points) Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer. (5 points)
Mathematics
2 answers:
Andrei [34K]3 years ago
4 0

Hey there! I'm happy to help!

PART A

Let's look at our two equations.

y=3x-5

y=6x-8

We will solve this with substitution because we have two different values for y, so it will be be very easy to substitute.

We know that y is equal to 6x-8. This means that we can replace the y in the first equation with 6x-8 and then solve for x.

6x-8=3x-5

We add 8 to both sides.

6x=3x+3

We subtract 3x from both sides.

3x=3

We divide both sides by 3.

x=1

We can plug this x-value into either of our equations to figure out what y is.

y=6(1)-8

y=6-8

y=-2

Therefore, our solution is x=1 and y= -2.

PART B

When graphing the two equations in a systems of equation, the point where they intersect is the solution. We already have our solution, so now we will just write it as a point, which is (1,-2).

Have a wonderful day! :D

Bumek [7]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

y = 3x − 5

y = 6x − 8

I will use substitution by substituting for y in the first equation

y = 3x − 5

6x -8 = 3x-5

Subtract 3x from each side

6x-3x -8 = 3x-5-3x

3x-8 = -5

Add 8 to each side

3x-8+8 = -5+8

3x =3

Divide by 3

3x/3= 3/3

x =1

Now find y

y = 3x − 5

  = 3(1) -5

  =3-5

  = -2

( 1,-2)

The two lines will intersect at ( 1,-2)

The solution to the two equations is where the lines intersect.

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Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

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