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Scilla [17]
3 years ago
7

The following table shows the expressions that represent the sales of 4 companies:

Mathematics
1 answer:
katen-ka-za [31]3 years ago
3 0

Answer: C. B, A, C, D


Step-by-step explanation:

We know that the exponential growth function is represented by :-

A(1+r)^x, where r is the growth rate.

The exponential decay function is represented by:-

A(1-r)^x, where r is the decay rate.

Now for Company A the sales function=340(1.03)^x=340(1+0.03)^x

⇒ It is a growth function with growth rate 0.03 or 3 %.

For Company B the sales function=275(0.89)^x=275(1-0.11)^x

⇒ It is a decay function with decay rate 0.11 or 11 %.

Similarly for Company C, there is growth rate of 0.23 or 23% and for Company D, there is growth rate of .90 or 90 %

Thus, the rank according to the sales by smallest to largest percent of increase will be B, A, C, D

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Answer:

12.0 units is the answer

Step-by-step explanation:

Pythagorean theorem can be written as,

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Rounding off,

d = 12.0 units

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3 years ago
The perimeter of this triangle
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Answer:

Perimeter = 3x+7

Step-by-step explanation:

x + x + (x+7) = (x+x+x) + 7

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What is the ratio for the volumes of two similar Pyramids, given that the ratio of the edge lengths is 8:3?
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Step-by-step explanation:

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7 0
3 years ago
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(URGENT) need this for today!​
Zigmanuir [339]

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right triangel

Step-by-step explanation:

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6 0
3 years ago
Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

3 0
3 years ago
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