The answer is B. 5.
There are five different types of cross sections of a cone possible.
Answer:
I believe it's parrolelegram rectangle and square
The equation of the quadratic function in standard form as required in the task content is; f(x) = -x² + 12x - 43.
<h3>Standard form equation of a quadratic function.</h3>
It follows from the task content that the standard form equation of the quadratic function is to.be determined.
Since the standard form equation can be derived from the vertex form equation as follows;
f(x) = a (x - h)² + k
f(x) = a (x - 6)² - 7
Hence, to find the value of a, Substitute x = 8 and f(x) = -11 so that we have;
-11 = a (8 - 6)² - 7
-11 = 4a - 7
4a = -4
a = -1.
Hence, the equation in vertex form is; f(x) = -1 (x -6)² - 7 and when expressed in standard form we have;
f(x) = -1(x² - 12x + 36) - 7
f(x) = -x² + 12x - 43
Therefore, the required equation in standard form is; f(x) = -x² + 12x - 43.
Read more on quadratic functions;
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Answer:
Domain is -3
Step-by-step explanation:
Given that coordinate of a graph is (-3, -2)
We have to find out the domain.
We know that if A and B are two sets, a mapping from A to B is the subset of cartesian product AxB.
Domain is the set of values of A which have images in B.
Use the above definition.
We have A = {-3,...} and B = {-2,....}
The mapping is from -3 to -2
Hence domain is -3
5x+4y= $35
x= daisies and y=roses
3x+6y=$39
