3(x-1)-8=4(1+x)+5
One solution was found :
x = -20
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*(x-1)-8-(4*(1+x)+5)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((3•(x-1))-8)-(4•(x+1)+5) = 0
Step 2 :
Equation at the end of step 2 :
(3 • (x - 1) - 8) - (4x + 9) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
-x - 20 = -1 • (x + 20)
Equation at the end of step 4 :
-x - 20 = 0
Step 5 :
Solving a Single Variable Equation :
5.1 Solve : -x-20 = 0
Add 20 to both sides of the equation :
-x = 20
Multiply both sides of the equation by (-1) : x = -20
One solution was found :
x = -20
hope this is wht u wanted
Answer:
what are the equations
Step-by-step explanation:
you didnt show the equations
Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
1. Participial
2. Gerund
3.participal
4.participal
4.infinitive
Answer:
In 10 seconds, the garden hose will emit 15 quarts of water.
Step-by-step explanation:
The amount of water emitted by the garden hose over time can be expressed as a ratio: 9/6, or 9 quarts of water for every 6 seconds of time. We can then simplify this ratio to 3/2, or 3 quarts of water for every 2 seconds of time. Since the ratio will remain constant, or the same, over time, we can set up an equivalent ratio, or fraction to find the amount of water emitted in 10 seconds: 3/2 = x/10. We look at the denominators and see that 2 x 5 = 10. In order to make the ratios equivalent, we would also multiply the numerator by 5: 3 x 5 = 15, which gives us the amount of water emitted in 10 seconds.
