Equation I
<span>y=5/2x is indirect variation b'cos as the value of x increases, the value of y decreases and vice versa </span>
<span>let us substitue x=5, then we get </span>
<span>y=5/2(5) </span>
<span>y=1/2 ==> 0.5 </span>
<span>let us substitute x=10, we now get </span>
<span>y=5/2(10) => 1/4 => 0.25 </span>
<span>Equation II </span>
<span>y=x+4 </span>
<span>this is direct variation cos as you increase the value of x, the value of y wud also increase and vice versa </span>
<span>let us substitute different values for x </span>
<span>let x be 7 </span>
<span>y=7+4 </span>
<span>y = 11 </span>
<span>let x be 2 </span>
<span>y=2+4 </span>
<span>y=6 </span>
<span>thus this is direct variation </span>
<span>Equation III </span>
<span>y=4... this is neither cos there is no x..</span>
Answer:
M = (-4, -5)
Step-by-step explanation:
M = (-2-6)/2 , (-10+0)/2
M = -8/2 , -10/2
M = (-4, -5)
Answer:
-∞ < x < ∞
Set of all integers
Step-by-step explanation:
Given in the question two functions
f(x) = 
= ∛x
g(x) = 3x + 1
(f*g)(x)
f(g(x))
∛(3x+1)
Domain of (f*g)(x)
In function ∛(3x+1) , variable x can be any integer.
so, the domain is set of all integers
-∞ < x < ∞
