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Viktor [21]
3 years ago
8

Arace car starts from rest and accelerates uniformly to a speed of 40 m/s in 8.

Physics
1 answer:
9966 [12]3 years ago
8 0

Answer:

160 m

Explanation:

For computing the distance first we have to determine the acceleration which is shown below:

v = u + at

where,

v = 0 = initial velocity

u = 40 = uniformly to a speed

t = 8 = time

So, the a is

= 40 ÷ 8

= 5 m/s

Now we have to use the distance formula i.e

d = ut + 1 ÷ 2 at^2

= 1 ÷2 × 5 × 8^2

= 160 m

Basically we have to applied the above formulas so that the distance could come

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In 8,450 seconds, the number of radioactive nuclei decreases to 1/16 of the number present initially. What is the half-life (in
almond37 [142]

Answer:

<h2>2113 seconds</h2>

Explanation:

The general decay equation is given as N = N_0e^{-\lambda t} \\\\, then;

\dfrac{N}{N_0} = e^{-\lambda t} \\ where;

N/N_0 is the fraction of the radioactive substance present = 1/16

\lambda is the decay constant

t is the time taken for decay to occur = 8,450s

Before we can find the half life of the material, we need to get the decay constant first.

Substituting the given values into the formula above, we will have;

\frac{1}{16} = e^{-\lambda(8450)}  \\\\Taking\ ln\ of \both \  sides\\\\ln(\frac{1}{16} ) =  ln(e^{-\lambda(8450)})  \\\\\\ln (\frac{1}{16} )  = -8450 \lambda\\\\\lambda = \frac{-2.7726}{-8450}\\ \\\lambda = 0.000328

Half life f the material is expressed as t_{1/2} = \frac{0.693}{\lambda}

t_{1/2} = \frac{0.693}{0.000328}

t_{1/2} = 2,112.8 secs

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Of the four states of matter, which has particles that are the most tightly packed together?
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A car traveling at 37m/s starts to decelerate steadily. It comes to a complete stop in 15 seconds. What is it’s acceleration
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<u>Answer</u>

The acceleration is

a=-2.5ms^{-2} to the nearest tenth

<u>Explanation</u>

Since the car was travelling at 37ms^{-1} before it starts to decelerate, the initial velocity is

u=37ms^{-1}.

The final velocity is v=0ms^{-1}, because the car came to a stop.

The time taken is t=15s.

Using the Newton's equation of linear motion,

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This implies that,

0=37 +a(15)

This gives us,

0-37=15a


\Rightarrow -37=15a


We divide both sides by 15 to get,

a=-\frac{37}{15}ms^{-2}

or

a=-2.46667ms^{-2}




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