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2 years ago

A quantitative description of kinematics involves using __ to describe the motion

Physics

2 answers:

dybincka [34]2 years ago

6 0

position

i hope this helps you

have a great day

Lady_Fox [76]2 years ago

5 0

Answer : a quantitative description of kinematics involves using position , time velocity and acceleration to describe the motion.

Explanation : Kinematics are mostly concerned with the geometrically possible motion of an object without consideration of the force and mass involved.

it is used to describe the position of the object , their velocities, time and their acceleration.

we know the equations of motion.

$v=u+at$ ....(I)

$s= ut+\dfrac{1}{2}at^{2}$ ....(II)

$v^{2}=u^{2}+2as$ ....(III)

Where, v = velocity

t = time

a = acceleration

s = position , distance

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The kinetic energy of a body of mass 15 kg is 30 joule. What is its momentum?

lys-0071 [83]

This problem is a piece o' cake, IF you know the formulas for both kinetic energy and momentum. So here they are:

Kinetic energy = (1/2) · (mass) · (speed²)

Momentum = (mass) · (speed)

So, now ... We know that

==> mass = 15 kg, and

==> kinetic energy = 30 Joules

Take those pieces of info and pluggum into the formula for kinetic energy:

Kinetic energy = (1/2) · (mass) · (speed²)

30 Joules = (1/2) · (15 kg) · (speed²)

60 Joules = (15 kg) · (speed²)

4 m²/s² = speed²

Speed = 2 m/s

THAT's all you need ! Now you can find momentum:

Momentum = (mass) · (speed)

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Momentum = 30 kg·m/s

(Notice that in this problem, although their units are different, the magnitude of the KE is equal to the magnitude of the momentum. When I saw this, I wondered whether that's always true. So I did a little more work, and I found out that it isn't ... it's a coincidence that's true for this problem and some others, but it's usually not true.)

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Answer:

The last two bearings are

49.50° and 104.02°

Explanation:

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here,

x, y and z represents the lengths of sides opposite to the angels X,Y and Z.

Thus we have,

$cos X=\frac{x^2-y^2-z^2}{-2yz}$

$cos X=\frac{y^2 + z^2-x^2}{2yz}$

substituting the values in the equation we get,

$cos X=\frac{2900^2 + 3700^2-1700^2}{2\times 2900\times 3700}$

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similarly,

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pentagon [3]

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$\bf \longrightarrow {v}^{2} = {u}^{2} + 2as \\ \\ \rm \longrightarrow {0}^{2} = {15}^{2} + 2 \times a \times 63 \\ \\ \rm \longrightarrow 0 = 225 + 126a \\ \\ \rm \longrightarrow 126a = - 225 \\ \\ \rm \longrightarrow a = - \dfrac{225}{126} \\ \\ \rm \longrightarrow a = - 1.78 \: m {s}^{ - 2}$

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