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3 years ago

No force is necessary to

Physics

1 answer:

igor_vitrenko [27]3 years ago

4 0

No force is necessary to keep a moving object moving (in a straight line at a constant speed).

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Tell the different energy transformations that happen in each of these items

Alik [6]

Answer:

Television: Electricity to light Toaster: Electricity to Heat

Explanation:

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3 years ago

1.5 x 10^3 standard notation

poizon [28]

Answer:

1500

Explanation:

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3 years ago

Helpp for number 6 please

Vanyuwa [196]

A neutral object contains no net charge, but still has many charged particles within the object, it just means that the charges cancel each other out.

7 0

3 years ago

A racquet ball with mass m = 0.256 kg is moving toward the wall at v = 11.8 m/s and at an angle of θ = 29° with respect to the h

icang [17]

Answer:

Part a)

$P = 5.72 kg m/s$

Part b)

$\Delta P = 2.93 kg m/s$

Part c)

$F = 44.4 N$

Part d)

$\Delta P = 5.02 kg m/s$

Part e)

$\Delta t = 0.113 s$

Part f)

$\Delta K = 0$

Explanation:

As we know that initial velocity of the ball is given as

$v = 11.8 cos29 \hat i + 11.8 sin29 \hat j$

$v_i = 10.3 \hat i + 5.72 \hat j$

Now final velocity of the system is given as

$v_f = 10.3\hat i - 5.72\hat j$

Part a)

now magnitude of initial momentum is given as

$P = mv$

$P = 0.256(11.8)$

$P = 5.72 kg m/s$

Part b)

Change in momentum is given as

$\Delta P = m(v_f - v_i)$

$\Delta P = 0.256(5.72 + 5.72)$

$\Delta P = 2.93 kg m/s$

Part c)

As we know that average force is defined as the rate of change in momentum

so here we have

$F = \frac{\Delta P}{\Delta t}$

$F = \frac{2.93}{0.066}$

$F = 44.4 N$

Part d)

Magnitude of change in momentum is given as

$\Delta P = m(v_f - v_i)$

$\Delta P = 0.256(7.8 + 11.8)$

$\Delta P = 5.02 kg m/s$

Part e)

As we know that in 2nd case the force is same as the initial force

so we will have

$\frac{\Delta P}{\Delta t} = F$

$\frac{5.02}{\Delta t} = 44.4$

$\Delta t = 0.113 s$

Part f)

Since this is elastic collision so change in kinetic energy must be ZERO

$\Delta K = 0$

8 0

3 years ago

See attachment for the question

Zarrin [17]

The acceleration of the body is provided by the tension in the rope.

<h3>What is centripetal acceleration?</h3>

The centripetal acceleration is given by a = v^2/r. v = velocity of the body, r = radius

a = (8.40 m/s)^2/(8.50 m)

a = 8.3 m/s^2

The tension in the rope is the force that provides the centripetal force in the rope.

Learn more of centripetal acceleration:brainly.com/question/14465119

#SPJ1

6 0

2 years ago