If the density of water does not vary and the vents range in depth from about 1500 m to 3200 m below the surface, then the gauge pressure at a 2452-m deep vent is 224.268 atm.
Calculation:
Step-1:
It is given that the vents range in depth from about 1500 m to 3200 m below the surface. If we are assuming that the density of water does not vary. Then it is required to calculate the gauge pressure at a 2452-m deep vent.
The gauge pressure at a particular depth of ocean water is calculated as:
Here 
is the density of water, P is the required pressure, h is the depth of water, and g is the gravitational acceleration.
Step-2:
Now we are substituting the values to calculate the pressure at the depth of 2452-m.
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Ir=Initial Intensity/Area of spread=Io4πr2
Ir∝1r2
It is seen from this expression that intensity is inversely proportional to the square of the distance. As we move away from the light source the intensity decreases at the rate of square of the distance from the source.
Brightness being the perception of intensity. more the intensity more bright the object is perceived and vice versa.
Answer:
It will take 0.01 s or 10 ms
Solution:
As per the question:
Length of the packet, L = 1,000 bytes = 
Distance, d = 2500 km = 
Speed of propagation, s = 
Transmission rate, R = 2 Mbps
Now,
Propagation time, t can be calculated as:
t = 10 ms
- In general, propagation time, t is given by:
- No, this delay is independent of the length of the packet.
- No, this delay is independent of the rate of transmission.
Answer:
Explanation:
Total distance covered = 25 + 15 = 40 m
Total time = 15 + 8 = 23 s
Average speed = total distance covered / total time
= 40 / 23
= 1.74 m / s
Total displacement = 25 - 15 = 10 m
Total time = 15 + 8 = 23 s
Average velocity = total displacement / total time
= 10 / 23
= .434 m / s to the right .
Covalent bonding occurs when pairs of electrons are shared by atoms.
