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Luden [163]
4 years ago
8

The total charge that an automobile battery can supply without being recharged is given in terms of Ampere-hours. A typical 12-V

battery has a rating of 48 A · h . Suppose you forget to turn off the headlights in your parked automobile. If each of the two headlights draws 3.4 A , find out the time before your battery is "dead". Answer in units of hours. Answer in units of h.
Physics
1 answer:
Lena [83]4 years ago
7 0

Answer:

about 12 1/2 hours

Explanation:

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What instrument can break down electromagnetic light into its constituent parts?
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C. Spectroscope 

Spectroscope is the instrument that can break down electromagnetic light into its constituent parts.

It is a device that helps us identify what things are made out of. It takes the light and splits it up into its component colors. 
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4 years ago
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What is geology >>>????
anastassius [24]

Answer:

the study of geological factors and the ways the earth

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An object has 16 N of force being applied to the right, 16 N of force being applied to the left, and 6 N of force being applied
umka2103 [35]

Answer:

the net force on the object is 6 N.

Explanation:

Given;

force applied to the right on the object, F_r = 16 N

force applied to the left of the object, F_l = 16 N

force applied downward on the object, F_d = 6 N

The net horizontal force on the object = F_r - F_l = 16N -16N = 0

The net vertical force on the object = 6 \ N \ downward

The net force on the object is calculated as;

F_{net}^2 = 6^2 + 0\\\\F_{net}^2 = 36\\\\F_{net} = \sqrt{36} \\\\F_{net} = 6 \ N

Therefore, the net force on the object is 6 N.

7 0
3 years ago
Thanks + BRAINLIST <br><br> Please need correct answer asappp
garik1379 [7]
(A) Standing waves are created by two identical waves reflecting off each other

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Hope this helps :)
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3 years ago
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A stone is dropped from the upper observation deck of a tower, 750 m above the ground. (assume g = 9.8 m/s2.) (a) find the dista
Gekata [30.6K]
(a) The stone moves by uniform accelerated motion, with constant acceleration g=9.81 m/s^2 directed downwards, and its initial vertical position at time t=0 is 750 m. So, the vertical position (in meters) at any time t can be written as
y(t)= y_0 -  \frac{1}{2}gt^2= 750 - 4.9 t^2

(b) The time the stone takes to reach the ground is the time at which the vertical position of the stone becomes zero: y(t)=0. So, we can write
750-4.9 t^2 = 0
from which we find the time t after which the stone reaches the ground:
t= \sqrt{\frac{750 m}{4.9 m/s^2 }}= 12.37 s

(c) The velocity of the stone at time t can be written as
v(t) = -gt
because it is an accelerated motion with initial speed zero. Substituting t=12.37 s, we find the final velocity of the stone:
v(12.37 s)=-(9.81 m/s^2)(12.37 s)=-121.3 m/s

(d) if the stone has an initial velocity of v_0 = 6 m/s, then its law of motion would be
y(t)=y_0 - v_0t -  \frac{1}{2}gt^2
and we can find the time it needs to reach the ground by requiring again y(t)=0:
0=750 - 6t - 4.9 t^2
which has two solutions: one is negative so we neglect it, while the second one is t=11.78 s, so this is the time after which the stone reaches the ground.

5 0
3 years ago
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