Answer:
-0.383 m
Explanation:
Diameter of cylinder = 4m therefore r = 2
height of cylinder ( H ) = 4 m
specific gravity = 0.6 ( assumed )
depth of immersion = 'h'
<u>Determine the metacentric height </u>
weight of cylinder in water = water displaced
= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h
= 0.6 * 4 = h
∴ h = 2.4 m
hence the depth of center of buoyancy from free space = h /2 = 1.2 m
The metacentric height can be calculated using the formula below
Gm = Io / Vsubmerged - BG
attached below is the remaining solution
Answer:
less
Explanation:
Sliding friction is always less than static friction. This is because in sliding friction, the bodies slide with each other and thus the effect of friction is not more. However, it does not happen in the case of static friction.
Answer:as per as Newtons second law, The forces exerted on the rope create tension.
As such,The tension is equal to the applied force.The tension is trasmitted to the opposite side and of the rope delivering the applied force.
Hope this helps.. :)
My answer is "Watt per square meter".
Answer:
5.0 m/s
Explanation:
The horizontal motion of the salmon is uniform, so the horizontal component of the salmon's velocity is constant and it is
where u is the initial speed and 
. The horizontal distance travelled by the salmon is
where d = 1.95 m and t is the time needed to reach the final point.
Re-arranging for t,
(1)
Along the vertical direction, the equation of motion is
where:
y = 0.311 m is the final height reached by the salmon
h = 0 is the initial height
is the vertical component of the initial velocity of the salmon
is the acceleration of gravity
t is the time
Substituting t as found in eq.(1), we get the equation
and we can solve this formula for u, the initial speed of the salmon:
