I'm pretty sure its transverse waves
Answer:
The question is incomplete. However, I believe, it is asking for the acceleration of the elevator. This is 3.16 m/s².
Explanation:
By Hooke's law, ![F = ke](https://tex.z-dn.net/?f=F%20%3D%20ke)
F is the force on a spring, k is the spring constant and e is the extension or compression.
From the question,
![F = (1.08\text{ kN/m}) \times (6.0 \times 10^{-2}\text{ m}) = 64.8 \text{ N}](https://tex.z-dn.net/?f=F%20%3D%20%281.08%5Ctext%7B%20kN%2Fm%7D%29%20%5Ctimes%20%286.0%20%5Ctimes%2010%5E%7B-2%7D%5Ctext%7B%20m%7D%29%20%3D%2064.8%20%5Ctext%7B%20N%7D)
This is the force on the mass suspended on the spring. Its acceleration, a, is given by
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
![a = \dfrac{F}{m}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7BF%7D%7Bm%7D)
![a = \dfrac{64.8 \text{ N}}{5\text{ kg}} = 12.96\text{ m/s}^2](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7B64.8%20%5Ctext%7B%20N%7D%7D%7B5%5Ctext%7B%20kg%7D%7D%20%3D%2012.96%5Ctext%7B%20m%2Fs%7D%5E2)
This acceleration is more than the acceleration due to gravity, g = 9.8 m/s². Hence the elevator must be moving up with an acceleration of
12.96 - 9.8 m/s² = 3.16 m/s²
Looks like you need to review through the lesson and take notes as it tells you in the lesson what each of these are.
Answer:
What is the centripetal acceleration of the tip of the fan blade?
6.0 m/s2
48 m/s2
53 m/s2
96 m/s2
Answer is 96
Explanation: