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3 years ago

A square has sides of length (2 a-b) metres. Write down an expression for the area of the square and simplify it

Mathematics

1 answer:

Lorico [155]3 years ago

7 0

Answer:

A = 4a² - 4ab + b²

Step-by-step explanation:

The area (A) of a square is calculated as

A = s² ( s is the side length ) , so

A = (2a - b)² ← expand using FOIL

= (2a)² - 2ab - 2ab + (- b)²

= 4a² - 4ab + b²

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Sixteen is divided by the sum of a number q and 1

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What is the rule for the reflection? rx-axis(x, y) Ă˘â€ â€™ (Ă˘â‚¬"x, y) ry-axis(x, y) Ă˘â€ â€™ (Ă˘â‚¬"x, y) rx-axis(x, y) Ă˘â€

malfutka [58]

The rule for the reflection is explained below. The correct option will be x-axis (x, y) = (x, -y).

In real life, we think of a reflection as a mirror image, like when we look at own reflection in the mirror.

This idea of reflection correlating with a mirror image is similar in math.

<h3>Reflection Over the X Axis </h3>

A reflection of a point, a line, or a figure in the X axis involved reflecting the image over the x axis to create a mirror image.

In this case, the x axis would be called the axis of reflection.

The rule for reflecting over the X axis is to negate the value of the y-coordinate of each point, but leave the x-value the same.

When point P with coordinates (5,4) is reflecting across the X axis and mapped onto point P’, the coordinates of P’ are (5,-4).

Notice that the x-coordinate for both points did not change, but the value of the y-coordinate changed from 4 to -4.

<h3>Reflection Over the Y Axis </h3>

A reflection of a point, a line, or a figure in the Y axis involved reflecting the image over the Y axis to create a mirror image.

In this case, the Y axis would be called the axis of reflection.

The rule for reflecting over the Y axis is to negate the value of the x-coordinate of each point, but leave the y-value the same.

when point P with coordinates (5,4) is reflecting across the Y axis and mapped onto point P’, the coordinates of P’ are (-5,4).

Notice that the y-coordinate for both points did not change, but the value of the x-coordinate changed from 5 to -5.

Hence the correct option is r x-axis(x, y) = (x, -y).

For more details on reflection follow the link:

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2 years ago

Think about the function f(x) = 3 - 2x

Angelina_Jolie [31]

f(0) means the function output when the input is x = 0. This is the same as saying the y value when x = 0.

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f(0) = 3-2(0)

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The point (0,3) is on the graph. This is the y intercept which is where the graph crosses the y axis. The y intercept always occurs when x = 0.

So in other words, the special name for f(0) is the y intercept.

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3 years ago

Read 2 more answers

NEED HELP I need to fill in the highlighted parts

Gemiola [76]

The statements and reasons why the given statements are true are presented in the following two column proofs;

Question 1

Given: 9·(x + 6) - 41 = 75

$Prove \ x = \dfrac{62}{9}$

Statement ${}$ Reason

S1. 9·(x + 6) - 41 = 75 ${}$ R1. Given

S2. 9·(x + 6) = 116 ${}$ R2. Addition property

S3. 9·x + 54 = 116 ${}$ R3. Distributive property

S4. 9·x = 62 ${}$ R4. Subtraction property

S5. $x = \dfrac{62}{9}$ ${}$ R5. Division property of equality

Question 2.

Statement ${}$ Reason

S1. m∠A + m∠B = m∠D ${}$ R1. Given

S2. ∠C and ∠D form a Linear Pair ${}$ R2. Definition of linear pair

S3. ∠C and ∠D are supplementary ${}$ R3. Linear pair ∠s are supplementary

S4. ∠C + ∠D = 180° ${}$ R4. Definition of supplementary

S5. m∠C + m∠A + m∠B = 180° ${}$ R5. Substitution property

Question 3.

Statement ${}$ Reason

S1. ∠BDA ≅ ∠A ${}$ R1. Given

S2. ∠BDA ≅ ∠CDE ${}$ R2. Vertical angle theorem

S3. ∠CDE ≅ ∠A ${}$ R3. Transitive property of congruency

S4. m∠CDE = m∠A ${}$ R4. Definition of congruency

S5. (13·x + 20)° = (14·x + 15)° ${}$ R5. Substitution Property of Equality

S6. 14·x° = 13·x + 5° ${}$ R6. Subtraction property

S7. x = 5 ${}$ R7. Subtraction property

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3 years ago

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Luden [163]

Answer:

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Step-by-step explanation:

4) S and Z

5) A line that goes vertical and then goes to the right

see this:

---------------

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2 years ago

A square has sides of length (2 a-b) metres. Write down an expression for the area of the square and simplify it​

A square has sides of length (2 a-b) metres. Write down an expression for the area of the square and simplify it