This falls under geometry. The two labeled angles are congruent, which means the line segment between them (AD in the image) is a bisector of the angle at vertex A. Use the angle bisector theorem, which says that
Answer:
Step-by-step explanation:
(-8a - 1)- (-7a + 5) = -8a - 1 - 7a*(-1) + 5*(-1) { (-1) is disturbed to all the terms in (-7a +5)}
= -8a - 1 + 7a - 5
= -8a + 7a -1 - 5 {Combine like terms}
= -a - 6
Use the given functions to set up and simplify
h(8). The answer is −22. Hope this help! :)
Given:
m∠APD = (7x + 1)°
m∠DPC = 90°
m∠CPB = (9x - 7)°
To find:
The measure of arc ACD.
Solution:
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠APD + m∠DPC + m∠CPB = 180°
7x° + 1° + 90° + 9x° - 7° = 180°
16x° + 84° = 180°
Subtract 84° from both sides.
16x° + 84° - 84° = 180° - 84°
16x° = 96°
Divide by 16° on both sides.
x = 6
m∠APB = 180°
m∠BPD = (9x - 7)° + 90°
= (9(6) - 7)° + 90°
= 47° + 90°
m∠BPD = 137°
m∠APD = m∠APB + m∠BPD
= 180° + 137°
= 317°
<em>The measure of the central angle is congruent to the measure of the intercepted arc.</em>
m(ar ACD) = m∠APD
m(ar ACD) = 317°
The arc measure of ACD is 317°.
