Question

REALLY NEED HELP IM STUCK. I PUT A PICTURE

Answer 1

Just look at the x and y variables and their exponents and roots. Ignore the rest.

Start with x.
On the left side you have cubic root of x^c.
On the right side you have x^2.

$\sqrt[3]{x^c} = x^2$

$(x^c)^{\frac{1}{3}} = x^2$

$\dfrac{c}{3} = 2$

$c = 6$

Now look at y on both sides and the roots and exponents of y.

$\sqrt[3]{y^5} = y\sqrt[3]{y^d}$

$(y^5)^{\frac{1}{3}} = y^1 \times y^{\frac{d}{3}}$

$y^{\frac{5}{3}} = y^{1 + \frac{d}{3}}$

$y^{\frac{5}{3}} = y^{\frac{3}{3} + \frac{d}{3}}$

$y^{\frac{5}{3}} = y^{\frac{d + 3}{3}}$

$\dfrac{d + 3}{3} = \dfrac{5}{3}$

$d + 3 = 5$

$d = 2$

Answer: Choice C. c = 6; d = 2