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kolezko [41]
4 years ago
15

HURRY I WILL MARK BRAINLIEST

Mathematics
2 answers:
Novosadov [1.4K]4 years ago
6 0

Answer:

A is $40

B is 20 days

Step-by-step explanation:

A.

$15+($5*5)

$15+$25

$40

B.

$40/$2

20

uysha [10]4 years ago
5 0

Answer: A) 10$ B) 5 days

Step-by-step explanation:

A) If you deposit 5 dollars per day for five days, you can show this by 5 x 5 = $25. If you account currently has -$15 and you are adding $25, you will have $10.

B) If you now have $10 after you made all you deposits, you will need 5 days to withdraw $2 from your account until $0. This is because you can equally divide $10 / $2 to equal 5 days.

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What's the slope (-3,6),(-3,4)
xxTIMURxx [149]

Answer:

undefined

Step-by-step explanation:

Here,

x1 = - 3

y1 = 6

x2 = - 3

y2 = 4

Formula : -

Slope = ( y2 - y1 ) / ( x2 - x1 )

Slope

= ( 4 - 6 ) / ( - 3 - ( - 3 )

= - 2 / 0

= undefined

3 0
3 years ago
Read 2 more answers
Find the approximate side length of a square game board with an area of 118 in2.
storchak [24]

Answer:29.5 29.5 29.5 29.5 29.5 29.5 29.5 29.5

8 0
2 years ago
Please i need help
zmey [24]

Answer:

24 rows

Step-by-step explanation:

384 seats in total, and 16 chairs in a row, so 384/ 16=

24 rows

Hope this helps!

LMK if it does

5 0
3 years ago
Suppose u and v are functions of x that are differentiable at x=0 and that u(0)= 7,u'(0)=-5,v(0)= -1, v'(0)= -4.
andriy [413]

This question is incomplete, the complete question is;

Suppose u and v are functions of x that are differentiable at x=0

and that { u(0) = 7, u'(0) = -5 }  { v(0)= -1, v'(0) = -4 }

Find the values of the following derivatives at x = 0.

a) \frac{d}{dx}( uv )

b)  \frac{d}{dx}( \frac{u}{v} )

c)  \frac{d}{dx}( \frac{v}{u} )

Answer:

a) \frac{d}{dx}( uv ) = -23  

b) \frac{d}{dx}( \frac{u}{v} )  = 33

c) \frac{d}{dx}( \frac{v}{u} ) = -32/49 or - 0.6531

Step-by-step explanation:

Given that;

{ u(0) = 7, u'(0) = -5 }  { v(0)= -1, v'(0) = -4 }

a)

\frac{d}{dx}( uv )

we differentiate

\frac{d}{dx}( uv )  = uv' + vu'

at x = (0), we substitute our values

\frac{d}{dx}( uv ) = ( 7 × -4 ) + ( -1 × -5)

\frac{d}{dx}( uv )  = -28 + 5

\frac{d}{dx}( uv ) = -23  

b)

\frac{d}{dx}( \frac{u}{v} )

we differentiate

\frac{d}{dx}( \frac{u}{v} ) = ( vu' - uv' ) / v²

at x=0, we substitute our values

\frac{d}{dx}( \frac{u}{v} ) = ( (-1 × -5) - (7 × -4 ) ) / (-1)²

\frac{d}{dx}( \frac{u}{v} ) = (( 5 - ( -28 )) / 1

\frac{d}{dx}( \frac{u}{v} )  = 33 / 1

\frac{d}{dx}( \frac{u}{v} )  = 33

c) \frac{d}{dx}( \frac{v}{u} )

we differentiate

\frac{d}{dx}( \frac{v}{u} )  = ( uv' - vu' ) / u²

at x=0, we substitute our values

\frac{d}{dx}( \frac{v}{u} )  = ( (7 × -4) - (-1 × -4) ) / (7)²

\frac{d}{dx}( \frac{v}{u} ) = ( -28 - ( 4 ) ) / 49

\frac{d}{dx}( \frac{v}{u} )  = ( -28 - 4 ) /49

\frac{d}{dx}( \frac{v}{u} )  = -32 / 49

\frac{d}{dx}( \frac{v}{u} ) = -32/49 or - 0.6531

6 0
3 years ago
Brainliest if possible!<br> Evaluate ƒ(x) when x = 6.<br> 6<br> 12<br> 74<br> 218
Serjik [45]
So 6 is in the range of of the first equation so you substitute it there.
f(6) = 6(6)^2 + 2
6(36) + 2
216 + 2
218
8 0
3 years ago
Read 2 more answers
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