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Damm [24]
4 years ago
12

You are looking for an apartment to rent starting the

Mathematics
1 answer:
sweet [91]4 years ago
8 0
2 months, 600 x2 = 1200+1000 =2200
850 x2 = 1700+500 = 2200
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What is the greatest perfect square that is a factor of 396? Explain
DedPeter [7]
<span>To find the greatest perfect square  that is a factor of 396, first we check what are the factors of 396
Factors of 396 are: 1,2,3,4,6,9,11,12,18,22,33,36,44,66,99,132,198,396
Now we check which is the greatest perfect square in these. 
396, 198, 132, 99, 66,44 are not perfect square,
so 36 is the largest perfect square from the factors of 396, 6 x 6 = 6</span>² = 36
4 0
3 years ago
BRAINLY PLS HELP ME OUT ON THE 5,2 what the m value I beg you ASP
Snowcat [4.5K]

Answer:

hypotenuse = 5

height = 2

Using Pythagoras theorem,

5² = 2² + m²

=> 25 = 4 + m²

=> 25–4 = m²

=> √21 = m

=> m = 4.58

Value of m is 4.58

8 0
3 years ago
Simplify these expressions.<br> a. 4x + 7x + (–x)<br> b. –5yz + yz + 2yz
salantis [7]

Answer:A. 10x. B. -2yz

Step-by-step explanation:

A. 4x+7x=11x

11x+(-x) = 11x-1x=10x

B. -5yz+yz=-4yz

-4yz+2yz=-2yz

4 0
3 years ago
alo had the third highest grade oint avwrage (GPA) of a group of five. His GPA was 79, amd ir was 12 points lower thank the high
soldier1979 [14.2K]
The fourth highest GPA is 6
8 0
3 years ago
A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 0.8 ft/s,
shusha [124]

Answer:

-0.133 radians/s is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall.

Step-by-step explanation:

Let

x= distance between the wall and ladder

Ф = angle between the ladder and ground

The rate of change is: dx/dt = 0.8 ft/s

We need to find dФ/dt when x = 8 ft/s

From the triangle in the figure we see that:

cos Ф = x/10

=> x = 10 cosФ

Now, the rate of change will be

d(x)/dt = d/dt (10cosФ)

dx/dt = -10 sin Ф dФ/dt

dx/dt = 0.8 (given)

to find dФ/dt

we need to find sin Ф when x = 8

By Pythagoras theorem

(hypotenuse)^2 = (Perpendicular)^2+(base)^2

(10)^2 = (8)^2+ (Perpendicular)^2

100 = 64 +  (Perpendicular)^2

=>  (Perpendicular)^2 = 100-64

(Perpendicular)^2 = 36

Perpendicular = 6

sin Ф = Perpendicular/hypotenuse

sin Ф = 6/10 = 3/5

Putting values in:

dx/dt = -10 sin Ф dФ/dt

0.8 = -10(3/5) dФ/dt

0.8 = -6 dФ/dt

=> dФ/dt = 0.8 / -6

dФ/dt = - 0.133 radians/s

So, -0.133 radians/s is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall.

3 0
3 years ago
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