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3 years ago

Please help me solve this by today I'm in a hurry

Mathematics

1 answer:

Ghella [55]3 years ago

3 0

Answer:

The 3rd one

Step-by-step explanation:

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Implicit differentiation of 1/x +1/y=5 y(4)= 4/19<br> y'(4)=?

Aneli [31]

$\frac{1}{x} +\frac{1}{y} = 5\\\\x^{-1}+y^{-1}=5\\$

Above, I changed the fraction form of x and y into exponential form so it is easier to see the differentiation. Now, we can differentiate:

$-1x^{-2}+-1y^{-2}\frac{dy}{dx}=5\\\\\frac{-1}{x^2}-\frac{1}{y^2}\frac{dy}{dx}=5\\\\-\frac{1}{y^2}\frac{dy}{dx}=5+\frac{1}{x^2}\\\\\frac{dy}{dx}=-5y^2-\frac{y^2}{x^2}$

Now that we have dy/dx, we can plug in the x, which is 4, and the y, which is 4/19. We know these values of x and y because your question stated y(4) = 4/19.

$\frac{dy}{dx}=-5(\frac{4}{19})^2-\frac{(\frac{4}{19})^2}{(4)^2}\\\\\frac{dy}{dx}=-5(\frac{16}{361})-\frac{(\frac{16}{361})}{16}\\\\\frac{dy}{dx}=\frac{-80}{361}-\frac{1}{361}\\\\\frac{dy}{dx}=\frac{-81}{361}$

5 0

3 years ago

Which phrase best describes the translation from the graph y = 2(x - 15)2 + 3 to the graph of y = 2(x - 11)2 + 3?

ivolga24 [154]

Answer:

4 units to the left

Step-by-step explanation:

y = a (x - h)² + k

The h is a horizontal translation of <em>h</em> units.

For h > 0, move right

For h < 0, move left

8 0

3 years ago

Please help

Gala2k [10]

Answer:

Step-by-step explanation:

There is 180 degrees in a triangle.

65 + 65 = 130

180 - 130 = 50

6 0

3 years ago

Read 2 more answers

the height of a ball dropped from a 160 foot building after t seconds is represented by h(t)=160-16t^2.how high will the ball be

alekssr [168]

Answer:

The height of the ball after 3 secs of dropping is 16 feet.

Step-by-step explanation:

Given:

height from which the ball is dropped = 160 foot

Time = t seconds

Function h(t)=160-16t^2.

To Find:

High will the ball be after 3 seconds = ?

Solution:

Here the time ‘t’ is already given to us as 3 secs.

We also have the relationship between the height and time given to us in the question.

So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:

$h(3)=160-16(3)^2$

$h(3)=160-16 \times 9$

h(3)=160-144

h(3)=16

Therefore, the height of the ball after 3 secs of dropping is 16 feet.

8 0

3 years ago

I'm new to the app. Stumped on all of these

nekit [7.7K]

What are you stumped on?

3 0

3 years ago

Please help me solve this by today I'm in a hurry ​

Please help me solve this by today I'm in a hurry