Explain how to write an equival3nt expresion using the associative property 2+(11+y)
1 answer:
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=[(sinx/cosx)/(1+1/cosx)] + [(1+1/cosx)/(sinx/cosx)]
=[(sinx/cosx)/(cosx+1/cosx)]+[(cosx+1/cosx)/(sinx/cosx)]
= [sinx/(cosx+1)] + [(cosx+1)/sinx]
= [sin^2x+(cosx+1)^2] / [sinx (cosx+1)]
= [2+2cosx] / [sinx(cosx+1)]
=[2(cosx+1)] / [sinx (cosx+1)]
= 2/sinx
= 2 cscx
(I think this will be helpful for you. if you can see the picture, it has more detail in it.)
=[(sinx/cosx)/(cosx+1/cosx)]+[(cosx+1/cosx)/(sinx/cosx)]
= [sinx/(cosx+1)] + [(cosx+1)/sinx]
= [sin^2x+(cosx+1)^2] / [sinx (cosx+1)]
= [2+2cosx] / [sinx(cosx+1)]
=[2(cosx+1)] / [sinx (cosx+1)]
= 2/sinx
= 2 cscx
(I think this will be helpful for you. if you can see the picture, it has more detail in it.)
The horse traveled 439.6 feet after walking around the track 5 times
<u><em>Solution:</em></u>
Given that, horse walks around a circular track while its trainer stands in the center
The trainer is 14 feet from the horse at all times
Therefore, radius of circular track = 14 feet
The circumference of circle is the distance traveled by horse for 1 lap
<em><u>The circumference of circle is given as:</u></em>
Where, "r" is the radius and is a constant equal to 3.14
Thus the distance traveled by horse for one time in circular track is 87.92 feet
<em><u>About how far had the horse traveled after walking around the track 5 times? </u></em>
Multiply the circumference by 5
Thus the horse traveled 439.6 feet after walking around the track 5 times