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Vikki [24]
3 years ago
5

No stars have been found with masses greater than 300 times our Sun because A. they shine exclusively at X-ray wavelengths and b

ecome difficult to detect. B. they would fragment into binary stars because of their rapid rotation. C. they are not bright enough to be seen nearby. D. they would generate so much power that they would blow themselves apart. E. molecular clouds do not have enough material to form such massive stars.
Physics
1 answer:
valina [46]3 years ago
7 0

Answer:

D)they would generate so much power that they would blow themselves apart.

Explanation:

Stars contains helium and hydrogen gases with helium forming a large percentage. When a star is a few times greater than the Sun it could cause it to collapse into a black hole.

However when the mass of the star is 200 times greater than the sun, it means a larger percentage of helium gas which is formed by the fusion of hydrogen nuclei with a large amount of energy being the by product of this fusion process. This would make the Stars generate so much power that they would blow themselves apart.

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What is the American psychology Association ethical principle of psychology and code of conduct based upon
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A V = 108-V source is connected in series with an R = 1.1-kΩ resistor and an L = 34-H inductor and the current is allowed to rea
soldi70 [24.7K]

Answer:

Explanation:

Given an RL circuit

A voltage source of.

V = 108V

A resistor of resistance

R = 1.1-kΩ = 1100 Ω

And inductor of inductance

L = 34 H

After he inductance has been fully charged, the switch is open and it connected to the resistor in their own circuit, so as to discharge the inductor

A. Time the inductor current will reduce to 12% of it's initial current

Let the initial charge current be Io

Then, final current is

I = 12% of Io

I = 0.12Io

I / Io = 0.12

The current in an inductor RL circuit is given as

I = Io ( 1—exp(-t/τ)

Where τ is time constant and it is given as

τ = L/R = 34/1100 = 0.03091A

So,

I = Io ( 1—exp(-t/τ))

I / Io = ( 1—exp(-t/τ))

Where I/Io = 0.12

0.12 = 1—exp(-t/τ)

0.12 — 1 = —exp(-t/τ)

-0.88 = -exp(-t/0.03091)

0.88 = exp(-t/0.03091)

Take In of both sides

In(0.88) = In(exp(-t/0.03091)

-0.12783 = -t/0.030901

t = -0.12783 × 0.030901

t = 3.95 × 10^-3 seconds

t = 3.95 ms

B. Energy stored in inductor is given as

U = ½Li²

So, the current at this time t = 3.95ms

I = Io ( 1—exp(-t/τ))

Where Io = V/R

Io = 108/1100 = 0.0982 A

Now,

I = Io ( 1—exp(-t/τ))

I = 0.0982(1 — exp(-3.95 × 10^-3 / 0.030901))

I = 0.0982(1—exp(-0.12783)

I = 0.0982 × 0.12

I = 0.01178

I = 11.78mA

Therefore,

U = ½Li²

U = ½ × 34 × 0.01178²

U = 2.36 × 10^-3 J

U = 2.36 mJ

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3 years ago
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kakasveta [241]

Explanation:

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Speed of sound.

Direction.

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Answer fast please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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I believe it's the the third one. :)
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