Answer:
0.003060 cm³
Explanation:
Mass of water = m = 326.75 gram
Density of water = ρ = 1.00 g/mL = 1 g/cm³
density = mass / volume
⇒volume = density / mass
⇒volume = 1 / 326.75
⇒Volume = 0.0030604 cm³
∴ Volume held by beaker = 0.0030604 cm³
Here the combined mass of the beaker and water is given so the volume found will be of the beaker as well as the liquid. But, it can be seen that the volume is so small that subtracting the beaker mass would have negligible effect.
The force required to start an object sliding across a uniform horizontal surface is larger than the force required to keep the object sliding at a constant velocity once it starts.
The magnitudes of the required forces are different in these situations because the force of kinetic friction is less than the force of static friction. <em>(d)</em>
It means that you consider the elements as a list organized by atomic number, the property is seen to repeat over and over as you move through that list.
Because its a vacuum, there's no air resistance, they will fall at same time
Applying gravity acceleration rule g=9.8m/s which is taken as 10m/s sometimes.
Absolute Zero.
Kelvin 0 is Absolute Zero, the atoms cannot physically become any closer.
Celsius -273.15
