What is the American psychology Association ethical principle of psychology and code of conduct based upon

A test charge of -1.4 x 10-7 coulombs experiences a force of 5.4 x 10-1 newtons. Calculate the magnitude of the electric field c

VARVARA [1.3K]

Answer:

3.86×10⁶ Newton/coulombs

Explaination:

Applying,

E = F/q....................... Equation 1

Where E = Electric Field, F = Force, q = charge.

From the question,

Given: F = 5.4×10⁻¹ N, q = -1.4×10⁻⁷ coulombs

Substitute these values into equation 1

E = 5.4×10⁻¹/ -1.4×10⁻⁷

E = -3.86×10⁶ Newtons/coulombs

Hence the magnitude of the electric field created by the

negative test charge is 3.86×10⁶ Newton/coulombs

5 0

2 years ago

The internuclear distance between two closest Ar atoms in solid argon is about 3.8 A. The polarizability of argon is 1.66e-30 m3

oee [108]

Answer:

83.72 K

Explanation:

$\alpha$ = Polarizability of argon = $1.66\times 10^{-30}\ m^3$

I = First ionization = 1521 kJ/mol

r = Distance between atoms = 3.8 A

R = Gas constant = 8.314 J/mol K

T = Boiling point

Potential energy due to dispersion of gas is given by

$P=-\frac{3}{4}\frac{\alpha^2I}{r^6}\\\Rightarrow P=-\frac{3}{4}\frac{(1.66\times 10^{-30})^2\times 1521\times 10^3}{(3.8\times 10^{-10})^6}\\\Rightarrow P=-1044.01\ J/mol$

Kinetic energy is given by

$K=\frac{3}{2}RT$

The potential and kinetic energy will balance each other

$P=\frac{3}{2}RT\\\Rightarrow 1.04401\times 10^{-33}=\frac{3}{2}RT\\\Rightarrow T=\frac{1044.01\times 2}{3\times 8.314}\\\Rightarrow T=83.72\ K$

The boiling point of argon is 83.72 K

7 0

2 years ago

Two cylindrical resistors are made from same material and have the same length. When connected across the same battery, one diss

Ilia_Sergeevich [38]

Answer:

$\frac{d_2}{d_1} = \sqrt2 = 1.41$

Explanation:

As resistor is connected to the battery of constant EMF then the power across the resistor is given as

$P = \frac{E^2}{R}$

now if two resistors are made up of same material and of same length then due to different cross sectional area they both have different resistance

Due to different resistance they both will have different power

Since power is inversely depends on the resistance

So if the power is twice that of the other then the resistance must be half

so we have

$R_1 = \rho \frac{L}{A_1}$

$R_2 = \rho\frac{L}{A_2}$

since one resistance is half that of other resistance

So the area of one must be twice that of other

so we have

$\frac{A_2}{A_1} = 2$

$\frac{\pi d_2^2}{\pi d_1^2} = 2$

$d_2 = 1.41 d_1$

8 0

3 years ago

A rope pulls on a metal box at an angle of 60.0° with a force of 255 N. The box moves horizontally for 10.0 m. How much work was

N76 [4]

w = F•s•cos θ

= 255•10•cos 60°

= 255•10•½

= 1275 joule

7 0

3 years ago

Because the droplets are conductors, a droplet's positive and negative charges will separate while the droplet is in the region

BARSIC [14]

<span>Because the droplets are conductors, a droplet's positive and negative charges will separate while the droplet is in the region between the deflection plates. You are given a situation that if a neutral droplet passes between the plates. The droplet's dipole moment will point at the center of the droplet.</span>

3 0

3 years ago