Assume that,
The two angles of one triangle are congruent to two angles of a second triangle.
To prove: The third angles of the triangles are congruent.
Since, two angles of one triangle are congruent to two angles of a second triangle.
Therefore,

Adding these two we get,

Cancelling 180 on both sides, we get

Hence, if two angles of one triangle are congruent to two angles of a second triangle, the the third angles of the triangles are congruent.
Answer:
D
Step-by-step explanation:
Answer:
k = 1.75
Step-by-step explanation:
5 - 4k = -7
k = 1.75, because if you subtract 4 from both sides, you are left with 1.75 = -7.
If we divide 56 by 4 we get 14. Why by4? So that one number is 3 times the other So he had 14 balls that went into the green bags and 42 (56-14) that went into the red bags. We could just answer the question and say 14 but I think they want to know how many in each green bag.
14 and 42 don't work because they are not the same number of balls. What number is a common factor? 7 is,
We could have 2 green bags and split the 14 balls into 2 groups of 7 and with the remaining 42 - put them into 6 red bags of 7 each.
And so the answer to your question is:
7 ball in each bag = 2 bags are green, and 6 bags are red
14 balls + 42 balls = 56 bouncy balls
Answer:
264 with a remainder of 4
Step-by-step explanation: