Question

How do you do this equation and get the right answer. In algebra two I’m confused about this problem

Answer 1

Answer:

$\frac{-17}{9}$

Step-by-step explanation:

You're not using the f(x) function for this problem.

Let's look at what the problem is asking. It says you must evaluate the function g(x) for 1/3. Basically, this means you plug in 1/3 every time there is an x.

So, your new equation is:

g($\frac{1}{3}$) =($\frac{1}{3}$)^2 - 2

($\frac{1}{3}$)^2 = $\frac{1}{9}$

To subtract two from this, you need a common denominator. This means we need to get -2 to have a denominator of 9. Multiply the numerator and denominator (1) by 9 to get $\frac{-18}{9}$.

Then, subtract.

$\frac{1}{9}$  $\frac{-18}{9}$  = -17/9.