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Elena L [17]
3 years ago
5

Consider a circle that has a circumference of 28/3.14 centimeters. What is the area of this circle? Answer fast plz also can you

show work???
Mathematics
1 answer:
bija089 [108]3 years ago
7 0

Answer:

A=6.33\ cm^2

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

C=2\pi r

we have

C=\frac{28}{3.14}\ cm

\pi=3.14

substitute the values

\frac{28}{3.14}=2(3.14)r

r=\frac{28}{19.7192}\ cm

r=1.42\ cm

step 2

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

substitute the values

A=(3.14)(1.42)^{2}

A=6.33\ cm^2

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Mariana [72]
-----------------------------------------------
Information Given:
-----------------------------------------------
ON = 7x - 9
LM = 6x + 4
MN = x - 7
OL = 2y - 7

-----------------------------------------------
Since it is a parallelogram:
-----------------------------------------------
ON = LM and
MN = OL

-----------------------------------------------
ON = LM:
-----------------------------------------------
7x - 9 = 6x + 4

-----------------------------------------------
Subtract 6x from both sides:
-----------------------------------------------
x - 9 = 4

-----------------------------------------------
Add 9 to both sides:
-----------------------------------------------
x = 13

-----------------------------------------------
MN = OL:
-----------------------------------------------
x - 7 = 2y - 7

-----------------------------------------------
Sub x = 13:
-----------------------------------------------
13 - 7 = 2y - 7

-----------------------------------------------
Simplify:
-----------------------------------------------
6 = 2y - 7

-----------------------------------------------
Add 7 on both sides:
-----------------------------------------------
13 = 2y

-----------------------------------------------
Divide by 2:
-----------------------------------------------
y = 13/2

-----------------------------------------------
Answer: x = 13, y = 13/2 (Answer D)
-----------------------------------------------


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