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3 years ago

15

A sports arena can hold 18500 people, plus or minus 1200 people. Write an absolute value equation to represent the number of peo

ple that can attend an event.

1 answer:

Whitepunk [10]3 years ago

3 0

The solutions are only there if u need them

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A model is made of a car. The car is 9 feet long and the model is 6 inches long. What is the ratio of the length of the car to t

velikii [3]

Answer:

B

Step-by-step explanation:

To answer this, we need to see the to see to the fact that they are both in the same unit before we can take the ratio.

Firstly, we know that 1 foot = 12 inches. 9 feet would this be 9 * 12 = 108 inches.

Now we are told to get the ratio of length of car to length of model.

This means 108:6 = 18:1

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3 years ago

Read 2 more answers

megan pick 34 flowers. some of the flowers are yellow and 18 flower are pink. how many of the flowers are yellow

olchik [2.2K]

16 flowers are yellow

4 0

3 years ago

Kallisto built a rectangular sign that measured 2 and 3/4. The width is 1 and 1/4 shorter than the length. To find the area, mul

prisoha [69]

Answer:

<em>l</em> = 1 5/16

w = 1/16

A = 21/16 x 1/16 = 21/256

Step-by-step explanation:

Perimeter = 11/4

<em>l</em> = length

w = <em>l</em> - 5/4

2<em>l</em> + 2(<em>l</em> - 5/4) = 11/4

2<em>l</em> + 2<em>l</em> - -5/2 = 1/4

multiply each side by 4

8<em>l</em> + 8<em>l </em>- 10 = 11<em> </em>

16<em>l</em> = 21

<em>l</em> = 21/16 or 1 5/16

width = 21/16 - 20/16 = 1/16

8 0

3 years ago

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

<em>l</em> denotes length
<em>b</em> denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0

3 years ago

What is 247,039 rounded to the nearest thousand

DerKrebs [107]

<span><u><em>Answer:</em></u>
247,000

<u><em>Explanation:</em></u>
To round a number to the nearest thousand, we check the digit in the <u>hundreds position</u>:
1- If the digit is <u>less than 5</u>, then we round down. This means that we simply convert all digits after the thousands to zero and that's it
2- If the digit is <u>equal to or more than 5</u>, then we round up. This means that we add one to the thousands digit and then convert all digits after the thousands to zero.

In the given number 247039, the number in the hundreds position is 0. This means that we will <u>round down
</u>
Therefore, 246039 rounded to the nearest thousand would simply give 247000

Hope this helps :)</span>

6 0

3 years ago