All categories

3 years ago

Help me please. Will name brainliest.

Mathematics

2 answers:

mr Goodwill [35]3 years ago

7 0

Answer:

Step-by-step explanation:

If you simplify you get -45=75 and that’s not true.

Marizza181 [45]3 years ago

3 0

Answer:

A 15x -45 = 15x+75

Step-by-step explanation:

When there is no solution the x coefficients are the same but the constants are different

15x -45 = 15x+75

Subtract 15x from each side

15x-15x -45 = 15x-15x+75

-45 = 75

This is never true so there is no value of x that can be put into the equation that will make this true

You might be interested in

PLEASEEE HELP!!!!!!!!

Cloud [144]

Answer:

Number 2

Step-by-step explanation:

So you first gotta open the parentheses: When you multiply them you add the exponents

You get x^5/6 + 2x^7/3

8 0

3 years ago

Read 2 more answers

If sec x = -2 and x is an angle in the second quadrant find tangent

faltersainse [42]

Answer:

ndnvndvkfnvnvndnvnvncxncnnc

Step-by-step explanation:

ndkkvdjv jnfbfbfnbfnvnfncnncvnfnfc

6 0

3 years ago

Which expression is equivalent to sqrt2/^3sqrt2

zimovet [89]

The given expression is $\frac{\sqrt{2}}{\sqrt[3]{2}}$

This can be simplified using the radical properties as below

$\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\$

Now using exponent properties we can write

$\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\$

7 0

3 years ago

Read 2 more answers

Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this problem.A cube-shaped bin has

KonstantinChe [14]

This is the work shown with the answer. I hope this helps. God bless

6 0

3 years ago

Okay so there isn’t a square root of -1/125 right?? Like- am I just missing something or..?

Dmitry_Shevchenko [17]

I don’t think so because I’m pretty sure you can not square a negative, the fraction is kinda throwing me off

7 0

2 years ago