first of all we have the 5th term and 2nd term
T5=768 =a*r^4
T2=-12=a*r ^1
make a subject of formula in the both equations
that is a=T2/r and T5/r^4
a=12/r and a=768/r^4
when u equate them u will get
-64=r^3 so r=-4 then to find a that is 1st term
since second term is T2=a*r=12 an r=-4 then
a=12/-4 hence a=-3
Hello,
x=r cos t
y=r sin t
x²+y²=r²
r=4 cos t
r=4x/r==>x²+y²=4x
==>(x-2)²+y²=4 (a circle center (2,0),radius 2)
Answer:
6 people
Step-by-step explanation:
8/40 = x/32
multiply both sides by 32: 8(32)/40 = x
x = 256/40
= 6.4
≈ 6
my answer would be 10, but I might be wrong
