Since it's even, the integral from -7 to -1 is the same as the integral from 1 to 7.
think about
x^2 from 0..1,its 1/3
from 0..7 its 7^3/3
from -1..7 its 7^3/3+1/3

from -7..-1 of x^2 its -1/3+7^3/3 to get this without integrating we just do 7^3/3-1/3 which is the integral from 0..7 minus the integral from 0..1
So the integral from 1 to 0 f(x) dx = 5 changes to the integral from 0 to 1 f(x) dx = -5 and you add it to the integral from 0 to 7 which is 1 making -4

4 0

3 years ago

PLS HELP!! WILL MAKE BRAINLIEST!!!!

poizon [28]

Answer:

(86.2,0) is the x-intercept.

Step-by-step explanation:

You can use the slope formula to figure this one out:

Just use two of the points on the table, any of them will work:

$(33,-22)\\(52,-33)$

$\frac{-22-33}{33-52} =\frac{-55}{-19}=\frac{55}{19}$

Now you have the slope of the equation, now using the y-intercept equation you can substitute the variables for point of the table and the new slope.:

$(71,-44)\\y=mx+b\\-44=\frac{55}{19} (71)+b$

Now just solve for b to get the y intercept:

$-44=\frac{55}{19}(71)+b\\-44= \frac{3905}{19} +b\\(-\frac{3905}{19})-44=\frac{3905}{19} +b(-\frac{3905}{19})\\ -\frac{4741}{19}=b$

Now you have the y-intercept so you just have to plug in 0 to the y spot and it will calculate the x-intercept.

$0=\frac{55}{19}x-\frac{4741}{19}\\(+\frac{4741}{19})0=\frac{55}{19}x-\frac{4741}{19}(+\frac{4741}{19})\\\\\frac{4741}{19}=\frac{55}{19}x\\\frac{\frac{4741}{19}}{\frac{55}{19} }= \frac{\frac{55}{19} x}{\frac{55}{19} } \\\frac{431}{5} =x\\or\\86.2=x$