Answer:
0.25m
Explanation:
Using the expression that relates the angular velocity(w) and the linear velocity (v).
v= wr where;
w is the angular speed= 128rad/s
v is the linear speed = 32m/s
r is the radius
r = v/w
r = 32/128
r = 0.25m
The radius of the blade is 0.25m
<h3><u>Answer;</u></h3>
C) Covalent bonds are generally weaker than ionic bonds because they overlap electrons to fill their outer shell.
<h3><u>Explanation;</u></h3>
- <em><u>Covalent bond is a type of bond that results from the sharing of electrons between two non-metal atoms. </u></em>
- <em><u>Ionic bond on the other is a type of bond that results from the transfer of electrons between metal atoms and non metal atoms, where a metal atom looses electrons and a non-metal atom gains electrons.</u></em>
- <em><u>The amount of energy required to break an given bond determines how strong a particular bond is.</u></em> Ionic bonds require more energy to break as compared to covalent bond and therefore they are stronger than the covalent bonds.
Answer: An atom valence electron shell determines its chemical reactivity.
Explanation:
An atom's valence electron shell determines its chemical reactivity. The amount of electrons in the outermost shell of an atom is its valence electron and it determines how reactive the atom is.
The reactivity of an atom depends on the number of electrons in its outermost shell. Atoms that has their outermost electrons full e.g noble gases like argon, krypton etc are unreactive because there is no room for the atom to donate or accept any electron.
Elements like sodium and chlorine are reactive because they possesses 1 and 7 electrons in their outermost shell respectively as such they can donate and accept electrons making them reactive elements.
Answer:
F = 150.6 N
Rx = 63.65 N
Ry = - 115.5 N
orientation is - 61.14 degree with horizontal
Explanation:
given data
moment arm m = 2 cm
angel = 115 degree
distance = 13 cm
force = 21 N
to find out
muscle force, vertical component force , horizontal component force , orientation
solution
we consider here Ra and Rb is reaction upside and
we know moment formula that is
moment at joint = F × sin(θ) × m - force × distance
0 = F × sin(115) × 2 - 21 × 13
F = 150.6 N
so
for horizontal component
sum of horizontal force = Rx + Fcosθ
0 = Rx + (150.6) cos115
Rx = 63.65 N
and
for vertical component
sum of vertical force = Ry + Fsinθ
0 = Ry + (150.6) sin(115)
Ry = - 115.5 N
and
reaction direction are
tan∅ = Ry / Rx
tan∅ = -115.5 / 63.65
∅ = - 61.14 degree
so orientation is - 61.14 degree with horizontal