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Klio2033 [76]
3 years ago
9

A rock weighing 98 newtons is pushed off the edge of a bridge 50 meters above the ground. What was the potential energy of the r

ock before it began to fall?
Physics
2 answers:
barxatty [35]3 years ago
5 0

<u>Answer:</u> The potential energy of the rock before it began to fall is 4900 J

<u>Explanation:</u>

Force is defined as the mass multiplied by the acceleration of the object.

F=mg

where,

F = force exerted on the object

m = mass of the object

g = acceleration due to gravity

Potential energy is defined as the energy possessed due to the height of the object.

Mathematically,

E_p=mgh

Or,

E_p=F\times h

where,

E_p = potential energy of the rock = ?

F = force applied on the rock = 98 N

h = height of the bridge from where the rock is thrown = 50 m

Putting values in above equation, we get:

E_p=98N\times 50m\\\\E_p=4900J

Hence, the potential energy of the rock before it began to fall is 4900 J

lidiya [134]3 years ago
4 0
Ep = 4900 because Ep = wh
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Answer:

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Explanation:

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Now H-h = 42.3 - 0.2 = 42.1 cm = 0.421 m

The final velocity will be the initial velocity

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Acceleration of the frog is 2065.005 m/s²

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An electron, starting from rest and moving with a constant acceleration, travels 2.0 cm in 5.0 ms. What is the magnitude of this
IrinaK [193]
 <span>s=2.7 centimeters = 0.027 meters 
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s=(1/2)a*t^2 
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A school bus transporting students to school is an example of
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The last one, Kinetic energy bc it is taking them to school
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Suppose the entire solar nebula had cooled to 50 K before the solar wind cleared the early solar system of its gases. How would
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Suppose the entire solar nebula had cooled to 50 K before the solar wind cleared the early solar system of its gases. How would the composition and sizes of the planets of the inner solar system be different from what we see today is given below

Explanation:

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3 years ago
Use Newton's laws to explain why a falling object dropped from a 57m tower accelerates initially but then reaches constant veloc
snow_lady [41]

Answer:

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As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out

The body then moves at a constant uniform motion down according to Newton's first law

Explanation:

At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g

As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force

Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.

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