The metal component of the given compound, CrCl3, is chromium. The number of moles per 1 g of chromium is calculated through the equation below,
n = (1 g Cr)(1 mol Cr/51.996 g Cr)
n = 0.0192 mol Cr(3 electrons/1 mol Cr)
n = 0.0577 e-
Determine the number in charge by multiplying with Faraday's constant,
C = (0.0577 mol Cr)((1 F/1 mol e-)(96485 C/ 1F)
C = 5,566.87 C
Then, calculate time by dividing the charge with the current,
t = 5566.87 C/1.5 A
t = 3711.25 minutes
t = 61.84 hours
<span><em>Answer: 61.84 hours</em></span>
Answer:
Explanation:
a. Oxidation : 2O + 4e^- ------> 2O^2-
b. Reduction: 2Sr - 4e- -------> Sr^2+
c. Balanced redox reaction
2Sr + O2 ------------> 2Sr O
Oxidation and reduction can be defined by various means, addition of oxygen, removal of hydrogen, removal of electrons. For this reaction, this definition is used, oxidation is the loss of electrons while reduction is the gaining of electrons.
In (a) oxidation half reaction, the valency of oxygen is zero and then moves into lossing two electrons resulting into -2 valency.
In (b) reduction half reaction, the valency of Sr is zero and gains electrons resulting into valency of 2.
In the overall redox reaction, Sr and O2 with valency of 0 each reacts together and form SrO with valency of 2 and -2 respectively, which gives 0 and then balances the equation.
Answer/ explanation :
The find the mass,
We use this formula
Number of mole = mass/ molar mass
Since number of mole = 3.25mol
Number of mass be x
Molar mass of H2SO4
H - 1.00784 * 2= 2.01568
S - 32.065
O - 15.999 * 4 = 63.996
Note there are 2 moles of H and 4 moles of O and 1 mole of S
Molar mass of H2SO4 = 2.01568 + 32.065 + 63.996
= 98.07668g/mol
Number of mole= 3.25mol
3.25 = x / 98.07668
x = 3.25 * 98.07668
= 318.749g
Therefore, the number of mass is 318.749g
