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Sergio [31]
3 years ago
12

Phillip throws a basketball up in the air and through a hoop. Because the ball is acted on by the force of gravity, the ball wil

l —
Chemistry
2 answers:
Diano4ka-milaya [45]3 years ago
3 0

Answer:

C

Explanation:

lys-0071 [83]3 years ago
3 0

Answer:

Fal down to the flour

Explanation:

Because of gravity their is weight that weight keeps us down to earth everything has weight even a leaf not only weight but the atmosphere is like a wall that keeps us safe from all the stuff in space.

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what is the molecular formula for a compound that is 39.99% carbon, 6.73% hydrogen, and 53.28% oxygen and has a molar mass of 18
4vir4ik [10]

Answer:

IDEK

Explanation:

5 0
2 years ago
Draw the Lewis structure for BCl3. How many single bonds, double bonds, triple bonds, and unshared pairs of electrons are on the
andreev551 [17]

Answer :  The number of single bonds, double bonds, triple bonds, and unshared pairs of electrons on the central atom are, 3, 0, 0 and 0 respectively.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, BCl_3

As we know that boron has '3' valence electrons and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in BCl_3 = 3 + 3(7) = 24

According to Lewis-dot structure, there are 6 number of bonding electrons and 18 number of non-bonding electrons.

From the Lewis-dot structure we conclude that,

The number of single bonds, double bonds, triple bonds, and unshared pairs of electrons on the central atom are, 3, 0, 0 and 0 respectively.

3 0
3 years ago
Silver sulfate (Ag2SO4) is slightly soluble in water and it partly dissolves at the equilibrium according to the following balan
natka813 [3]

Answer:

a) S = 0.0152 mol/L

b) S' = 4.734 g/L

Explanation:

  • Ag2SO4 ↔ 2Ag+  +  SO42-

           S                2S            S...............in the equilibrium

  • Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]

a) molar solubility:

⇒ Ksp = ( 2S) ² * S = 1.4 E-5

⇒ 4S² * S = 1.4 E-5

⇒ S = ∛ ( 1.4 E-5 / 4 )

⇒ S = 0.0152 mol/L

b) solubility ( S' ) in grams per liter:

∴ Mw Ag2SO4 = 311.799 g/mol

⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )

⇒ S' = 4.734 g/L

4 0
3 years ago
The discipline of chemistry has made agricultural chemicals, such as fertilizer and pesticides, available to society.
dlinn [17]
Well, you can't use this word for word, but a good answer would be something like:
Pesticides release harmful chemicals into the air, not only making it toxic and unsafe for us, but it also has the potential to kill off insects. This affects the ecosystem as well, as it reduces the available food source for larger animals such as birds, which in turn, affect another species.
4 0
3 years ago
Read 2 more answers
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The followin
Studentka2010 [4]

Answer : The initial rate for a reaction will be 3.63\times 10^{-4}Ms^{-1}

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B+C\rightarrow D+E

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b[C]^c

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

1.2\times 10^{-4}=k(0.40)^a(0.40)^b(0.40)^c ....(1)

Expression for rate law for second observation:

3.6\times 10^{-4}=k(0.40)^a(0.40)^b(1.20)^c ....(2)

Expression for rate law for third observation:

4.8\times 10^{-4}=k(0.80)^a(0.40)^b(0.40)^c ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-4}=k(0.80)^a(0.80)^b(0.40)^c ....(4)

Dividing 1 from 2, we get:

\frac{3.6\times 10^{-4}}{1.2\times 10^{-4}}=\frac{k(0.40)^a(0.40)^b(1.20)^c}{k(0.40)^a(0.40)^b(0.40)^c}\\\\3=3^c\\c=1

Dividing 1 from 3, we get:

\frac{4.8\times 10^{-4}}{1.2\times 10^{-4}}=\frac{k(0.80)^a(0.40)^b(0.40)^c}{k(0.40)^a(0.40)^b(0.40)^c}\\\\4=2^a\\a=2

Dividing 3 from 4, we get:

\frac{4.8\times 10^{-4}}{4.8\times 10^{-4}}=\frac{k(0.80)^a(0.40)^b(0.40)^c}{k(0.80)^a(0.80)^b(0.40)^c}\\\\1=2^b\\b=0

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^0[C]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

1.2\times 10^{-4}=k(0.40)^2(0.40)^0(0.40)^1

k=1.875\times 10^{-3}M^{-2}s^{-1}

Now we have to calculate the initial rate for a reaction that starts with 0.55 M of reagent A and 0.80 M of reagents B and C.

\text{Rate}=k[A]^2[B]^0[C]^1

\text{Rate}=(1.875\times 10^{-3})\times (0.55)^2(0.80)^0(0.80)^1

\text{Rate}=3.63\times 10^{-4}Ms^{-1}

Therefore, the initial rate for a reaction will be 3.63\times 10^{-4}Ms^{-1}

4 0
2 years ago
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