Answer:
0.0073 g
Explanation:
Considering:
Or,
Given :
For HCl :
Molarity = 0.010 M
Volume = 25 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 25×10⁻³ L
Thus, moles of HCl :
Moles of HCl = 0.00025 moles
Considering the reaction shown below as:-
2 moles of HCl reacts with 1 mole of 
So,
1 moles of HCl reacts with 1/2 mole of
Also,
0.00025 moles of HCl reacts with 
mole of
Mole of = 0.000125 moles
Molar mass of = 58.3197 g/mol
Mass = Moles*Molar mass = 
= 0.0073 g
Answer:
H₂SO₄
Explanation:
We have a compound formed by 0.475 g H, 7.557 g S, 15.107 g O. In order to determine the empirical formula, we have to follow a series of steps.
Step 1: Calculate the total mass of the compound
Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g
Total mass = 23.139 g
Step 2: Determine the percent composition.
H: (0.475g/23.139g) × 100% = 2.05%
S: (7.557g/23.139g) × 100% = 32.66%
O: (15.107g/23.139g) × 100% = 65.29%
Step 3: Divide each percentage by the atomic mass of the element
H: 2.05/1.01 = 2.03
S: 32.66/32.07 = 1.018
O: 65.29/16.00 = 4.081
Step 4: Divide all the numbers by the smallest one
H: 2.03/1.018 ≈ 2
S: 1.018/1.018 = 1
O: 4.081/1.018 ≈ 4
The empirical formula of the compound is H₂SO₄.
Identity and chemical properties
Answer:
C. the relative molecular mass of the compound
Explanation:
Like molecular formulas, empirical formulas are not unique and can describe a number of different chemical structures or isomers. <u>To determine an empirical formula, the relative molecular mass of the composition of its elements</u> can be used to mathematically determine their ratio.
Answer: 15768 seconds
Explanation: (50 years) x (365 da/yr) x (86,400 sec/da)
= (50 x 365 x 86,400) seconds
= 1.5768 x 10⁹ seconds
