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shutvik [7]
3 years ago
9

How many C atoms are there in 5.25 grams of a compound containing 92.26% C and 7.74% H?

Chemistry
1 answer:
Damm [24]3 years ago
7 0
Take 5.25 grams and give it proportionally to the carbon
0.9226 * 5.25 grams = 4.84 grams Carbon
Find the number of moles
(4.84 grams carbon)/(12.01 grams/mol) = 0.403 moles Carbon
The number of atoms in a mole of a substance is called Avogadro's number.
There are 6.022 * 10^23 atoms in one mole of anything
(0.403 moles Carbon) * (6.022 * 10^23 atoms/mole) = 2.43 * 10^23 atoms of Carbon
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A student measures the volume of a solution to be 0.01370 l. How many significant digits are in this measurement?
Mkey [24]

A student measures the volume of a solution to be 0.01370 have 5 significant digits in this measurement.

<h3>What are significant digits?</h3>

The significant digits are the minimum number from zero to nine for reporting any measurement where the digits are uncertain.

The significant digits starting from zero are not significant digits, decimal is not a significant digit, and ending zero after the decimal are significant digits.

Therefore, the student measures the volume of a solution to be 0.01370 5 significant digits are in this measurement.

Learn more about significant digits, here:

brainly.com/question/1658998

#SPJ4

7 0
2 years ago
Convert 15.4 moles of Ca3(PO4)2 to grams.
arlik [135]

Answer:

La cantidad de Ca3 (P04) 2 equivalente a 15, 4 moles es de 4774 gramos.

Explanation:

We need the weights of the elementos Ca, P and O, for calculate the weight of 1 mol:

Weight Ca=40 g

Weight P=31 g

Weight 0 = 16 g

Weight Ca3(PO4)2 = 3 x 40 g + 2 x (31 g + 4 x 16 g)

Weight Ca3(PO4)2 =310 g

1 molCa3(PO4)2---- 310 g

15, 4 mol Ca3(PO4)2-----x=(15, 4 molx 310 g)/1 mol = 4774 g

5 0
3 years ago
Water at a rate of 45,500 kg/h is heated from 80 to 150°C in a heat exchanger having two shell passes and eight tube passes with
Vlad [161]

Answer:

U = 129.053 KJ/m².h

Explanation:

overall heat transfer coefficient (U):

U = (<em>m</em>Cp(ToutH2O - TinH2O))/[A((ToutAir - TinH2O)-(TinAir - ToutH2O))/(Ln(ToutAir - TinH2O)/(TinAir - ToutH2O))]

∴ A = 925 m²

H2O:

∴ mass flow H2O (<em>m</em>) = 45500 Kg/h

∴ Cp H2O = 4186 J/Kg°C

∴ Tin = 80°C

∴ Tout = 150°C

Air:

∴ Tin = 350°C

∴ Tout = 175°C

⇒ U = ((45500Kg/h)(4186J/Kg°C)(150-80))/(925m²)[((175-80)-(350-150))Ln((175-80)/(350-150))]

⇒ U = (1.333 E10 J/h)/(925m²)[(-150)Ln(0.475)]

⇒ U = 129052.73 J/m².h = 129.053 KJ/m².h

4 0
3 years ago
An IMP system is used to​
ivolga24 [154]

Answer:

IMP Electronic Systems have provided the military and aerospace industries with the design, manufacture, repair, overhaul, and product improvement of avionics, electronic systems, and wire harness assemblies.

8 0
3 years ago
QUESTION 24<br> Calculate [H 30+] of a solution with a pH of 2.14.
sleet_krkn [62]

Answer:

The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find the pH. [H3O+] = 10-pH or [H3O+] = antilog (- pH).

I hope what I just explained is enough .

7 0
3 years ago
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